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What is the use for IHttpHandler.IsReusable?
I'm writing a IHttpHandler and I'll need to implement a IsReusable property. When I look at the MSDN documentation it says:
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How to detect the screen resolution with JavaScript?
...with the device pixel ratio: window.screen.width * window.devicePixelRatio and window.screen.height * window.devicePixelRatio. This will also work on desktops, which will have a ratio of 1.
And from Ben in another answer:
In vanilla JavaScript, this will give you the AVAILABLE width/height:
window...
Get value of a string after last slash in JavaScript
I am already trying for over an hour and cant figure out the right way to do it, although it is probably pretty easy:
10 An...
How to access component methods from “outside” in ReactJS?
...he component methods from “outside” in ReactJS? Why is it not possible and is there any way to solve it?
8 Answers
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Get last n lines of a file, similar to tail
I'm writing a log file viewer for a web application and for that I want to paginate through the lines of the log file. The items in the file are line based with the newest item on the bottom.
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Using ls to list directories and their total sizes
... it possible to use ls in Unix to list the total size of a sub-directory and all its contents as opposed to the usual 4K that (I assume) is just the directory file itself?
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How might I find the largest number contained in a JavaScript array?
... edited May 22 '19 at 21:07
Andy
5,53244 gold badges3838 silver badges5252 bronze badges
answered Sep 4 '09 at 14:19
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How to increase request timeout in IIS?
... @Jowen: You rock! I had earlier changed debug to false days ago and didn't associate it with all the timeout errors I'd been receiving. Now I know.
– Doug S
Oct 31 '15 at 4:45
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What is the most efficient way of finding all the factors of a number in Python?
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The reduce(list.__add__, ...) is taking the little lists of [fac1, fac2] and joining them together in one long list.
The [i, n/i] for i in range(1, int(sqrt(n)) + 1) if n % i == 0 returns a pair of factors if the remainder when you divide n by the smaller one is zero (it doesn't need to check the...
Most efficient way to concatenate strings?
...ike:
x = f1(...) + f2(...) + f3(...) + f4(...)
that's one concat and it's zippy, StringBuilder probably won't help.
If your pattern looks like:
if (...) x += f1(...)
if (...) x += f2(...)
if (...) x += f3(...)
if (...) x += f4(...)
then you probably want StringBuil...