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Print PHP Call Stack
I'm looking for a way to print the call stack in PHP.
15 Answers
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修改centos字符集导致桌面进不去的一系列问题 - 更多技术 - 清泛网 - 专注C...
修改centos字符集导致桌面进不去的一系列问题为了使 WINDOWS–PL SQL-LINUX–ORACLE 的字符集一致怎么修改WINDOWS下的 PL SQL 字符集请参看http: user.qzone.qq.com 587...为了使 WINDOWS –PL/SQL-LINUX –ORACLE 的字符集一致
怎么修改WINDOW...
How do I PHP-unserialize a jQuery-serialized form?
.... You do indeed need to parse the string that serialize returns. See the really popular answer below.
– Isaac Lubow
Mar 1 '19 at 2:17
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Refresh a page using PHP
How can I refresh a page using PHP periodically? If I can not do it by PHP, what is the best recommended scenario?
13 Answe...
Create subdomains on the fly with .htaccess (PHP)
...ches[1])) {
$subdomain = $matches[1];
}
I have used regex here to to allow for people hitting your site via www.subdomain.example.org or subdomain.example.org.
If you never anticipate having to deal with www. (or other subdomains) then you could simply use a substring like so:
$subdomain = s...
Determining Referer in PHP
...s the most reliable and secure way to determine what page either sent, or called (via AJAX), the current page. I don't want to use the $_SERVER['HTTP_REFERER'] , because of the (lack of) reliability, and I need the page being called to only come from requests originating on my site.
Edit: I am...
How to validate an Email in PHP?
...hould be replaced by the preg family (PCRE Regex Functions). There are a small amount of differences, reading the Manual should suffice.
Update 1: As pointed out by @binaryLV:
PHP 5.3.3 and 5.2.14 had a bug related to
FILTER_VALIDATE_EMAIL, which resulted in segfault when validating
large ...
warning C4996 - C/C++ - 清泛网 - 专注C/C++及内核技术
...可能会产生诸如内存泄露、缓冲区溢出、非法访问等安全问题。这些函数如：strcpy、strcat等。
对于这些问题，VC2005建议使用这些函数的更高级的安全版本，即在这些函数名后面加了一个_s的函数。这些安全版本函数使用起来更...
领域驱动设计系列（五）:事件驱动之异步事件 - 更多技术 - 清泛网 - 专注C/...
...可以看到，现在并行处理可以大大加快速度，但是有两个问题，第一个问题就是没有处理异常，所以让我们加上异常。
public void Publish<T>(T @event) where T : Event
{
var handlers = _eventHandlerFactory.GetHandlers<T>();
handlers....
How to get a variable name as a string in PHP?
...
Actually now that I've tested my code, my code always returned 'var' because it's being used in the function. When I use $GLOBALS instead, it returns the correct variable name for some reason. So I'll change the above code to use...