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How to generate random number with the specific length in python
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To get a random 3-digit number:
from random import randint
randint(100, 999) # randint is inclusive at both ends
(assuming you really meant three digits, rather than "up to three digits".)
To use an arbitrary number of digits:
from random import randint
def random_with_N_digits(n):
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MySQL IF NOT NULL, then display 1, else display 0
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ypercubeᵀᴹypercubeᵀᴹ
102k1414 gold badges155155 silver badges216216 bronze badges
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Determine if string is in list in JavaScript
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answered Mar 12 '10 at 1:56
SLaksSLaks
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iOS: Use a boolean in NSUserDefaults
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answered Oct 1 '10 at 16:34
Henrik P. HesselHenrik P. Hessel
34.4k1717 gold badges7676 silver badges9999 bronze badges
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Detect if a jQuery UI dialog box is open
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answered Jul 22 '10 at 21:51
Byron WhitlockByron Whitlock
48.4k2626 gold badges112112 silver badges164164 bronze badges
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Check if a string contains a substring in SQL Server 2005, using a stored procedure
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edited Mar 24 '10 at 9:20
answered Mar 24 '10 at 9:14
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Using comparison operators in Scala's pattern matching system
...i.e. an if and a boolean expression after the pattern:
a match {
case 10 => println("ten")
case x if x > 10 => println("greater than ten")
case _ => println("less than ten")
}
Edit: Note that this is more than superficially different to putting an if after the =>, becau...
What does the star operator mean, in a function call?
...m(a, b, c, d):
return a + b + c + d
values1 = (1, 2)
values2 = { 'c': 10, 'd': 15 }
s = sum(*values1, **values2)
will execute as:
s = sum(1, 2, c=10, d=15)
Also see section 4.7.4 - Unpacking Argument Lists of the Python documentation.
Additionally yo...
How can I check if multiplying two numbers in Java will cause an overflow?
...tle table I whipped up to check this, pretending that overflow happens at -10 or +10:
a = 5 b = 2 2 > 10 / 5
a = 2 b = 5 5 > 10 / 2
a = -5 b = 2 2 > -10 / -5
a = -2 b = 5 5 > -10 / -2
a = 5 b = -2 -2 < -10 / 5
a = 2 b = -5 -5 < -10 / ...
Replace values in list using Python [duplicate]
...but it doesn't actually save time:
items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
for index, item in enumerate(items):
if not (item % 2):
items[index] = None
Here are (Python 3.6.3) timings demonstrating the non-timesave:
In [1]: %%timeit
...: items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10...
