大约有 43,700 项符合查询结果（耗时：0.0306秒） [XML]
Pandas index column title or name
...0]:
Column 1
foo
Apples 1
Oranges 2
Puppies 3
Ducks 4
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How to round to 2 decimals with Python?
...the decimal point.
In your case, it would be:
answer = str(round(answer, 2))
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Rounding float in Ruby
...er, I can only use .round which basically turns it into an int, meaning 2.34.round # => 2. Is there a simple effect way to do something like 2.3465 # => 2.35
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What does tilde-greater-than (~>) mean in Ruby gem dependencies? [duplicate]
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207
It means "equal to or greater than in the last digit", so e.g. ~> 2.3 means
"equal to 2.3 o...
How to apply a function to two columns of Pandas dataframe
Suppose I have a df which has columns of 'ID', 'col_1', 'col_2' . And I define a function :
12 Answers
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Installing specific package versions with pip
I'm trying to install version 1.2.2 of the MySQL_python adaptor, using a fresh virtualenv created with the --no-site-packages option. The current version shown in PyPi is 1.2.3 . Is there a way to install the older version? I found an article stating that this should do it:
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How can I delete one element from an array by value
...
I think I've figured it out:
a = [3, 2, 4, 6, 3, 8]
a.delete(3)
#=> 3
a
#=> [2, 4, 6, 8]
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Sum a list of numbers in Python
I have a list of numbers such as [1,2,3,4,5...] , and I want to calculate (1+2)/2 and for the second, (2+3)/2 and the third,
(3+4)/2 , and so on. How can I do that?
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What is Weak Head Normal Form?
...ains no un-evaluated thunks).
These expressions are all in normal form:
42
(2, "hello")
\x -> (x + 1)
These expressions are not in normal form:
1 + 2 -- we could evaluate this to 3
(\x -> x + 1) 2 -- we could apply the function
"he" ++ "llo" -- we could apply...
how do I insert a column at a specific column index in pandas?
...e beginning
df.insert(loc, column, value)
df = pd.DataFrame({'B': [1, 2, 3], 'C': [4, 5, 6]})
df
Out:
B C
0 1 4
1 2 5
2 3 6
idx = 0
new_col = [7, 8, 9] # can be a list, a Series, an array or a scalar
df.insert(loc=idx, column='A', value=new_col)
df
Out:
A B C
0 7 1 4
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