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Purpose of returning by const value? [duplicate]

...on-const value, and you could write: (a + b).expensive(); In the age of C++11, however, it is strongly advised to return values as non-const so that you can take full advantage of rvalue references, which only make sense on non-constant rvalues. In summary, there is a rationale for this practice...
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Does Java have buffer overflows?

...s: If you call native code via JNI In the JVM itself (usually written in C++) The interpreter or JIT compiler does not work correctly (Java bytecode mandated bounds checks) share | improve this a...
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Generic type conversion FROM string

...I must point out that my experience with parameterised types is limited to C++ and its templates, but I imagine there is some way to do the same sort of thing using C# generics. share | improve this...
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Func vs. Action vs. Predicate [duplicate]

...sed with Linq, Action and Func are concepts logically independent of Linq. C++ already contained the basic concept in form of typed function pointers. Here is a small example for Action and Func without using Linq: class Program { static void Main(string[] args) { Action<int>...
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Memory address of variables in Java

...object has the same hashcode. I am confused because I have learned in c or c++ every variable or object have different memory location. Then in java How can identify or differentiate two objects with the same hashCode. – Ved Prakash Jun 8 '18 at 16:46 ...
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How do I flush the cin buffer?

How do I clear the cin buffer in C++? 13 Answers 13 ...
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How to declare a global variable in php?

...NTENT is attempted to modify? Is it just like final in Java or const in C, C++ and C#? – Lion Nov 23 '12 at 14:05 ...
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Cast to int vs floor

...t in the top-most bits being dropped (C, probably) or undefined behaviour (C++ and possibly C). EG if your int is 32 bits, you will only have a sign bit plus 31 bits of data. So using this with a double that is large in size is going to produce unintended results. ...
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Creating a “logical exclusive or” operator in Java

... Bear in mind that you can't define new operators in C++ either. All you can do is give new meanings to the old ones. – David Thornley Apr 7 '09 at 20:57
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Explicit specialization in non-namespace scope [duplicate]

... VC++ is non-compliant in this case - explicit specializations have to be at namespace scope. C++03, §14.7.3/2: An explicit specialization shall be declared in the namespace of which the template is a member, or, for membe...