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Comparing two NumPy arrays for equality, element-wise
What is the simplest way to compare two NumPy arrays for equality (where equality is defined as: A = B iff for all indices i: A[i] == B[i] )?
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What is the difference between a heuristic and an algorithm?
What is the difference between a heuristic and an algorithm?
12 Answers
12
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Scala 2.8 breakOut
In Scala 2.8 , there is an object in scala.collection.package.scala :
4 Answers
4
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Oracle “(+)” Operator
I am checking some old SQL Statements for the purpose of documenting them and probably enhancing them.
4 Answers
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With arrays, why is it the case that a[5] == 5[a]?
As Joel points out in Stack Overflow podcast #34 , in C Programming Language (aka: K & R), there is mention of this property of arrays in C: a[5] == 5[a]
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C++ equivalent of java's instanceof
What is the preferred method to achieve the C++ equivalent of java's instanceof ?
6 Answers
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C语言面试那些事儿──一道指针与数组问题 - C/C++ - 清泛网 - 专注C/C++及内核技术
...那些事儿──一道指针与数组问题首先看如下代码：int main(int argc, char** argv){ int a[5] = {1,2,3,4,5}; int* ptr = (int*)(&a + 1); ...首先看如下代码：
int main(int argc, char** argv)
{
int a[5] = {1,2,3,4,5};
int* ptr = (int*)(&a + 1);
printf("...
What is the difference between a strongly typed language and a statically typed language?
Also, does one imply the other?
8 Answers
8
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How to avoid overflow in expr. A * B - C * D
I need to compute an expression which looks like:
A*B - C*D , where their types are: signed long long int A, B, C, D;
Each number can be really big (not overflowing its type). While A*B could cause overflow, at same time expression A*B - C*D can be really small. How can I compute it correctly...
Why is there no tuple comprehension in Python?
As we all know, there's list comprehension, like
10 Answers
10
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