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edited Mar 28 '13 at 20:19
Brad Koch
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Replace specific characters within strings
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410
With a regular expression and the function gsub():
group <- c("12357e", "12575e", "197e18",...
Adding a new array element to a JSON object
...Object, then stringify back to JSON
var jsonStr = '{"theTeam":[{"teamId":"1","status":"pending"},{"teamId":"2","status":"member"},{"teamId":"3","status":"member"}]}';
var obj = JSON.parse(jsonStr);
obj['theTeam'].push({"teamId":"4","status":"pending"});
jsonStr = JSON.stringify(obj);
// "{"theTeam...
How can I combine hashes in Perl?
What is the best way to combine both hashes into %hash1? I always know that %hash2 and %hash1 always have unique keys. I would also prefer a single line of code if possible.
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Is JSON Hijacking still an issue in modern browsers?
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1 Answer
1
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Difference between numpy.array shape (R, 1) and (R,)
In numpy , some of the operations return in shape (R, 1) but some return (R,) . This will make matrix multiplication more tedious since explicit reshape is required. For example, given a matrix M , if we want to do numpy.dot(M[:,0], numpy.ones((1, R))) where R is the number of rows (of co...
How to concatenate properties from multiple JavaScript objects
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14 Answers
14
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Fold / Collapse the except code section in sublime text 2
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199
If you'll hover with the mouse over the line numbers you'll see arrows - clicking on any of th...
How do I check the difference, in seconds, between two dates?
...es, use total_seconds like this:
import datetime as dt
a = dt.datetime(2013,12,30,23,59,59)
b = dt.datetime(2013,12,31,23,59,59)
(b-a).total_seconds()
86400.0
#note that seconds doesn't give you what you want:
(b-a).seconds
0
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