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When to use Storyboard and when to use XIBs

... answered Nov 27 '14 at 10:20 thgcthgc 1,90511 gold badge1616 silver badges2323 bronze badges ...
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Any way to limit border length?

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Find an element in a list of tuples

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Algorithm to detect intersection of two rectangles?

...e = v(n) - v(n-1) You can get a perpendicular to this by rotating it by 90°. In 2D this is easy as: rotated.x = -unrotated.y rotated.y = unrotated.x So no trigonometry or slopes involved. Normalizing the vector to unit-length is not required either. If you want to test if a point is on o...
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WiX tricks and tips

...DIR)\Config.wxi?> <Product ... > <Package InstallerVersion="200" InstallPrivileges="elevated" InstallScope="perMachine" Platform="$(var.Platform)" Compressed="yes" Description="$(var.ProductName)" /> and <Directory Id="TARGETDIR" Name="SourceDir"> &l...
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Delete branches in Bitbucket

... answered Jul 27 '16 at 21:47 Ralf Rafael FrixRalf Rafael Frix 1,35933 gold badges2020 silver badges3131 bronze badges ...
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Error to run Android Studio

...ll went right the answer should be something like this: java version "1.8.0_91" Java(TM) SE Runtime Environment (build 1.8.0_91-b14) Java HotSpot(TM) 64-Bit Server VM (build 25.91-b14, mixed mode) Check what compiler is used javac -version It should show something like this javac 1.8.0_91 F...
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Why are Standard iterator ranges [begin, end) instead of [begin, end]?

... +50 The best argument easily is the one made by Dijkstra himself: You want the size of the range to be a simple difference end − beg...
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Difference between >>> and >>

...ss of the number. For example: -2 represented in 8 bits would be 11111110 (because the most significant bit has negative weight). Shifting it right one bit using arithmetic shift would give you 11111111, or -1. Logical right shift, however, does not care that the value could possibly represent ...
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How can I quantify difference between two images?

... img2 = to_grayscale(imread(file2).astype(float)) # compare n_m, n_0 = compare_images(img1, img2) print "Manhattan norm:", n_m, "/ per pixel:", n_m/img1.size print "Zero norm:", n_0, "/ per pixel:", n_0*1.0/img1.size How to compare. img1 and img2 are 2D SciPy arrays here: def comp...