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Why would I want stage before committing in Git?

...ther than adding it and then commiting it? – kiwicomb123 Aug 1 '17 at 16:27 1 ...
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How do I check if an object has a specific property in JavaScript?

...d for ( var prop in obj ) { document.writeln( "Object1: " + prop ); } function Class(){ this.a = undefined; this.b = null; this.c = false; } Class.prototype = { a: undefined, b: true, c: true, d: true, e: true }; var obj2 = new Class(); // a, b, c, d, e found ...
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Tracking the script execution time in PHP

... 123 Shorter version of talal7860's answer <?php // At start of script $time_start = microtime(...
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Split string every nth character?

... >>> line = '1234567890' >>> n = 2 >>> [line[i:i+n] for i in range(0, len(line), n)] ['12', '34', '56', '78', '90'] share | ...
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Putting HTML inside Html.ActionLink(), plus No Link Text?

... Craig StuntzCraig Stuntz 123k1212 gold badges244244 silver badges266266 bronze badges ...
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MySQL connection not working: 2002 No such file or directory

... Hmm. Maybe they meant Leopard or Tiger. In any case, have fun with WordPress! – Alec Gorge Nov 4 '09 at 21:47 3 ...
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Remap values in pandas column with a dict

...n-matched entries are changed to NaNs Although map most commonly takes a function as its argument, it can alternatively take a dictionary or series: Documentation for Pandas.series.map Non-Exhaustive Mapping If you have a non-exhaustive mapping and wish to retain the existing variables for non-...
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Use dynamic variable names in JavaScript

... a = 'varname'; str = a+' = '+'123'; eval(str) alert(varname); Try this... share | improve this answer | follow |...
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Semaphore vs. Monitors - what's the difference?

...tor is an object designed to be accessed from multiple threads. The member functions or methods of a monitor object will enforce mutual exclusion, so only one thread may be performing any action on the object at a given time. If one thread is currently executing a member function of the object then ...
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How to reverse a singly linked list using only two pointers?

... Any alternative? No, this is as simple as it gets, and there's no fundamentally-different way of doing it. This algorithm is already O(n) time, and you can't get any faster than that, as you must modify every node. It looks like your code is on the right track, but it's not quite working ...