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Move an array element from one array position to another
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+150
If you'd like a version on npm, array-move is the closest to this answer, although it's not the same implementation. See its usage sec...
Git Tag list, display commit sha1 hashes
...can run:
git show-ref --tags
The output will then look something like:
0e76920bea4381cfc676825f3143fdd5fcf8c21f refs/tags/1.0.0
5ce9639ead3a54bd1cc062963804e5bcfcfe1e83 refs/tags/1.1.0
591eceaf92f99f69ea402c4ca639605e60963ee6 refs/tags/1.2.0
40414f41d0fb89f7a0d2f17736a906943c05acc9 refs/tags/1.3...
How to insert element into arrays at specific position?
...on array operator (+) can recombine the parts.
$res = array_slice($array, 0, 3, true) +
array("my_key" => "my_value") +
array_slice($array, 3, count($array)-3, true);
This example:
$array = array(
'zero' => '0',
'one' => '1',
'two' => '2',
'three' => '3',
);
$...
Comparing numbers in Bash
...
answered Sep 7 '13 at 0:48
jordanmjordanm
25k44 gold badges5252 silver badges6363 bronze badges
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Determine font color based on background color
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20 Answers
20
Active
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Fastest way to flatten / un-flatten nested JSON objects
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+500
Here's my much shorter implementation:
Object.unflatten = function(data) {
"use strict";
if (Object(data) !== data || Array....
Reverse Range in Swift
...:to:by:) is similar but excludes the last value
for i in stride(from:5,to:0,by:-1) { print(i) } // 5 4 3 2 1
Update For latest Swift 2
First of all, protocol extensions change how reverse is used:
for i in (1...5).reverse() { print(i) } // 5 4 3 2 1
Stride has been reworked in Xcode 7 Beta 6. ...
Getting current date and time in JavaScript
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600
.getMonth() returns a zero-based number so to get the correct month you need to add 1, so calli...
How to calculate the number of occurrence of a given character in each row of a column of strings?
... 2
#2 2 magic 1
#3 3 not 0
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What is the most efficient way of finding all the factors of a number in Python?
...(reduce(list.__add__,
([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))
This will return all of the factors, very quickly, of a number n.
Why square root as the upper limit?
sqrt(x) * sqrt(x) = x. So if the two factors are the same, they're both the square root. If ...