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MFC CSplitterWnd的用法详解 - C/C++ - 清泛网 - 专注C/C++及内核技术

...user-defined views derived from CMDIView   m_wndSplitter.CreateView(0,0,RUNTIME_CLASS(COneView), CSize(0,0),    pContext);   m_wndSplitter.CreateView(1,0,RUNTIME_CLASS(CAnotherView), CSize(0,0),   pContext);   return (bCreateSpltr); } 或者: BOOL...
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Fastest way to flatten / un-flatten nested JSON objects

... +500 Here's my much shorter implementation: Object.unflatten = function(data) { "use strict"; if (Object(data) !== data || Array....
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Comparing numbers in Bash

... answered Sep 7 '13 at 0:48 jordanmjordanm 25k44 gold badges5252 silver badges6363 bronze badges ...
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Reverse Range in Swift

...:to:by:) is similar but excludes the last value for i in stride(from:5,to:0,by:-1) { print(i) } // 5 4 3 2 1 Update For latest Swift 2 First of all, protocol extensions change how reverse is used: for i in (1...5).reverse() { print(i) } // 5 4 3 2 1 Stride has been reworked in Xcode 7 Beta 6. ...
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clearing a char array c

... to view this as a C/C++ null terminated string, setting the first byte to 0 will effectively clear the string. share | improve this answer | follow | ...
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Are members of a C++ struct initialized to 0 by default?

... constructors struct Snapshot { int x; double y; Snapshot():x(0),y(0) { } // other ctors / functions... }; Will initialize both x and y to 0. Note that you can use x(), y() to initialize them disregarding of their type: That's then value initialization, and usually yields a proper...
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How to create a colored 1x1 UIImage on the iPhone dynamically?

...c image(with color: UIColor) -> UIImage { let rect = CGRectMake(0.0, 0.0, 1.0, 1.0) UIGraphicsBeginImageContext(rect.size) let context = UIGraphicsGetCurrentContext() CGContextSetFillColorWithColor(context, color.CGColor) CGContextFillRect(context, rect) ...
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How to calculate the number of occurrence of a given character in each row of a column of strings?

... 2 #2 2 magic 1 #3 3 not 0 share | improve this answer | follow | ...
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How do I check if there are duplicates in a flat list?

... 406 Use set() to remove duplicates if all values are hashable: >>> your_list = ['one', 't...
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What is the most efficient way of finding all the factors of a number in Python?

...(reduce(list.__add__, ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0))) This will return all of the factors, very quickly, of a number n. Why square root as the upper limit? sqrt(x) * sqrt(x) = x. So if the two factors are the same, they're both the square root. If ...