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MFC CSplitterWnd的用法详解 - C/C++ - 清泛网 - 专注C/C++及内核技术
...user-defined views derived from CMDIView
m_wndSplitter.CreateView(0,0,RUNTIME_CLASS(COneView), CSize(0,0),
pContext);
m_wndSplitter.CreateView(1,0,RUNTIME_CLASS(CAnotherView), CSize(0,0),
pContext);
return (bCreateSpltr);
}
或者:
BOOL...
Fastest way to flatten / un-flatten nested JSON objects
...
+500
Here's my much shorter implementation:
Object.unflatten = function(data) {
"use strict";
if (Object(data) !== data || Array....
Comparing numbers in Bash
...
answered Sep 7 '13 at 0:48
jordanmjordanm
25k44 gold badges5252 silver badges6363 bronze badges
...
Reverse Range in Swift
...:to:by:) is similar but excludes the last value
for i in stride(from:5,to:0,by:-1) { print(i) } // 5 4 3 2 1
Update For latest Swift 2
First of all, protocol extensions change how reverse is used:
for i in (1...5).reverse() { print(i) } // 5 4 3 2 1
Stride has been reworked in Xcode 7 Beta 6. ...
clearing a char array c
... to view this as a C/C++ null terminated string, setting the first byte to 0 will effectively clear the string.
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Are members of a C++ struct initialized to 0 by default?
... constructors
struct Snapshot {
int x;
double y;
Snapshot():x(0),y(0) { }
// other ctors / functions...
};
Will initialize both x and y to 0. Note that you can use x(), y() to initialize them disregarding of their type: That's then value initialization, and usually yields a proper...
How to create a colored 1x1 UIImage on the iPhone dynamically?
...c image(with color: UIColor) -> UIImage {
let rect = CGRectMake(0.0, 0.0, 1.0, 1.0)
UIGraphicsBeginImageContext(rect.size)
let context = UIGraphicsGetCurrentContext()
CGContextSetFillColorWithColor(context, color.CGColor)
CGContextFillRect(context, rect)
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How to calculate the number of occurrence of a given character in each row of a column of strings?
... 2
#2 2 magic 1
#3 3 not 0
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How do I check if there are duplicates in a flat list?
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406
Use set() to remove duplicates if all values are hashable:
>>> your_list = ['one', 't...
What is the most efficient way of finding all the factors of a number in Python?
...(reduce(list.__add__,
([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))
This will return all of the factors, very quickly, of a number n.
Why square root as the upper limit?
sqrt(x) * sqrt(x) = x. So if the two factors are the same, they're both the square root. If ...