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What is this: [Ljava.lang.Object;?
...f the class of which the object is an instance, the at-sign character `@', and the unsigned hexadecimal representation of the hash code of the object. In other words, this method returns a string equal to the value of:
getClass().getName() + '@' + Integer.toHexString(hashCode())
Note: you can no...
Is there a [Go to file…]?
... keyboard shortcut to open a file by typing its name without putting your hand on the mouse. For example:
7 Answers
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HTML / CSS How to add image icon to input type=“button”?
... right align an icon using <input type="button"> , so that the text and the image fit and align nicely?
12 Answers
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Dismissing a Presented View Controller
...sage on to the presenting view controller. If you want to do anything over and above just dismissing the VC, you will need to know this, and you need to treat it much the same way as a delegate method - as that's pretty much what it is, a baked-in somewhat inflexible delegate method.
Perhaps they'...
How to “add existing frameworks” in Xcode 4?
...get.
Select the "Build Phases" tab.
Open "Link Binaries With Libraries"
expander.
Click the + button.
Select your framework.
(optional) Drag and drop the added
framework to the "Frameworks" group.
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Visual Studio: How to show Overloads in IntelliSense?
...r a method is to actually edit the method by deleting the Parenthesis () and reopening them.
10 Answers
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Convert a JSON String to a HashMap
I'm using Java, and I have a String which is JSON:
18 Answers
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extra qualification error in C++
... need to change it to the following code to be able to compile it with a standard compliant compiler (gcc is more compliant to the standard on this point).
class JSONDeserializer
{
Value ParseValue(TDR type, const json_string& valueString);
};
The error come from the fact that JSONDeseria...
How do you suppress output in IPython Notebook?
...Good thing to know is %%capture is only enabled until the end of the cell, and it must appear before any code in the cell. (So it appears there isn't a way to uncapture within a cell.)
– Arel
Oct 17 '16 at 19:32
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How do I pass the value (not the reference) of a JS variable to a function? [duplicate]
...ange_selection(i);
});
})(i);
}
By creating an anonymous function and calling it with the variable as the first argument, you're passing-by-value to the function and creating a closure.
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