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How do you perform a left outer join using linq extension methods
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B--rian
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answered Feb 25 '09 at 5:44
Marc Gravell♦Marc Gravell
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python plot normal distribution
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216
import matplotlib.pyplot as plt
import numpy as np
import scipy.stats as stats
import math
mu...
How to export a Vagrant virtual machine to transfer it
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121
You have two ways to do this, I'll call it dirty way and clean way:
1. The dirty way
Create a...
Django REST framework: non-model serializer
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2 Answers
2
Active
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Swift Beta performance: sorting arrays
...ksort_swift(inout a:CInt[], start:Int, end:Int) {
if (end - start < 2){
return
}
var p = a[start + (end - start)/2]
var l = start
var r = end - 1
while (l <= r){
if (a[l] < p){
l += 1
continue
}
if (a[r] > p)...
How to get default gateway in Mac OSX
... similar to:
route to: 98.137.149.56
destination: default
mask: 128.0.0.0
gateway: 5.5.0.1
interface: tun0
flags: <UP,GATEWAY,DONE,STATIC,PRCLONING>
recvpipe sendpipe ssthresh rtt,msec rttvar hopcount mtu expire
0 0 0 0 ...
Fitting empirical distribution to theoretical ones with Scipy (Python)?
...teger values ranging from 0 to 47, inclusive, e.g. [0,0,0,0,..,1,1,1,1,...,2,2,2,2,...,47,47,47,...] sampled from some continuous distribution. The values in the list are not necessarily in order, but order doesn't matter for this problem.
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Counting the Number of keywords in a dictionary in python
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429
len(yourdict.keys())
or just
len(yourdict)
If you like to count unique words in the file, ...
Python list iterator behavior and next(iterator)
...nge(10)))
>>> for i in a:
... print(i)
... next(a)
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0
1
2
3
4
5
6
7
8
9
So 0 is the output of print(i), 1 the return value from next(), echoed by the interactive interpreter, etc. There are just 5 iterations, each iteration resulting in 2 lines being written to the terminal.
If...
How to sort an array in descending order in Ruby
...0.times {
ary << {:bar => rand(1000)}
}
n = 500
Benchmark.bm(20) do |x|
x.report("sort") { n.times { ary.sort{ |a,b| b[:bar] <=> a[:bar] } } }
x.report("sort reverse") { n.times { ary.sort{ |a,b| a[:bar] <=> b[:bar] }.reverse } }
x.report("sort_by ...