大约有 18,335 项符合查询结果（耗时：0.0346秒） [XML]
scopes with lambda and arguments in Rails 4 style?
...
I think it should be:
scope :find_lazy, -> (id) { where(id: id) }
share
|
improve this answer
|
follow
|
...
Difference between id and name attributes in HTML
What is the difference between the id and name attributes? They both seem to serve the same purpose of providing an identifier.
...
Finding duplicate rows in SQL Server
...tatement to grab all of these and the amount of dupes, but also return the ids that are associated with each organization.
...
Insert into a MySQL table or update if exists
...
Use INSERT ... ON DUPLICATE KEY UPDATE
QUERY:
INSERT INTO table (id, name, age) VALUES(1, "A", 19) ON DUPLICATE KEY UPDATE
name="A", age=19
share
|
improve this answer
|
...
App Inventor 2 DynamicComponents 拓展：动态创建AI2组件对象 · App Inventor 2 中文网
...不将其保存到已创建的组件列表中，因此它不会关联到 ID。请注意，你无法直接在 Screen 中创建组件，你需要事先在 Screen 中设置布局才能执行此操作。
将已创建组件的 ID...
Avoid duplicates in INSERT INTO SELECT query in SQL Server
...
Using NOT EXISTS:
INSERT INTO TABLE_2
(id, name)
SELECT t1.id,
t1.name
FROM TABLE_1 t1
WHERE NOT EXISTS(SELECT id
FROM TABLE_2 t2
WHERE t2.id = t1.id)
Using NOT IN:
INSERT INTO TABLE_2
(id, name)
SELECT t1.id,
...
How to create a date and time picker in Android? [closed]
Is there any android widget that enable to pick the date and the time at the same time ?
I already use the basic time picker and date picker .
...
Rails Model find where not equal
...
In Rails 4.x (See http://edgeguides.rubyonrails.org/active_record_querying.html#not-conditions)
GroupUser.where.not(user_id: me)
In Rails 3.x
GroupUser.where(GroupUser.arel_table[:user_id].not_eq(me))
To shorten the length, you could store GroupUser....
jquery selector for id starts with specific text [duplicate]
...
Use jquery starts with attribute selector
$('[id^=editDialog]')
Alternative solution - 1 (highly recommended)
A cleaner solution is to add a common class to each of the divs & use
$('.commonClass').
But you can use the first one if html markup is not in your ...
What is the “N+1 selects problem” in ORM (Object-Relational Mapping)?
...:
SELECT * FROM Cars;
And then for each Car:
SELECT * FROM Wheel WHERE CarId = ?
In other words, you have one select for the Cars, and then N additional selects, where N is the total number of cars.
Alternatively, one could get all wheels and perform the lookups in memory:
SELECT * FROM Wheel
Thi...