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How to iterate through two lists in parallel?
I have two iterables in Python, and I want to go over them in pairs:
8 Answers
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Lua简明教程 - 脚本技术 - 清泛IT论坛,有思想、有深度
...后,你会发现解释器居然不到200k,这是多么地变态啊(/bin/sh都要1M,MacOS平台),而且能和C语言非常好的互动。我很好奇得浏览了一下Lua解释器的源码,这可能是我看过最干净的C的源码了。我不想写一篇大而全的语言手册,一...
What is an undefined reference/unresolved external symbol error and how do I fix it?
What are undefined reference/unresolved external symbol errors? What are common causes and how to fix/prevent them?
34 Answ...
How to add an object to an array
How can I add an object to an array (in javascript or jquery)?
For example, what is the problem with this code?
13 Answ...
pandas: How do I split text in a column into multiple rows?
...file and the next to last column has a string of text that I want to split by a specific delimiter. I was wondering if there is a simple way to do this using pandas or python?
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Javascript array search and remove string?
...pdating this thread with a more recent 1-line solution:
let arr = ['A', 'B', 'C'];
arr = arr.filter(e => e !== 'B'); // will return ['A', 'C']
The idea is basically to filter the array by selecting all elements different to the element you want to remove.
Note: will remove all occurrences. ...
Why Would I Ever Need to Use C# Nested Classes [duplicate]
I'm trying to understand about nested classes in C#. I understand that a nested class is a class that is defined within another class, what I don't get is why I would ever need to do this.
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What is the difference between a string and a byte string?
I am working with a library which returns a byte string and I need to convert this to a string.
7 Answers
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I want to get the type of a variable at runtime
I want to get the type of a variable at runtime.
How do I do this?
4 Answers
4
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Swapping two variable value without using third variable
... y have different memory locations (rather than different values). This is because (p xor p) = 0 and if both x and y share the same memory location, when one is set to 0, both are set to 0.
When both *x and *y are 0, all other xor operations on *x and *y will equal 0 (as they are the same), which me...
