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CMake使用教程 - C/C++ - 清泛网 - 专注C/C++及内核技术
...Generate。
配置需要选择合适的编译器，虽然我安装了VC2008，但没有配置成功；选择Unix Makefiles，配置成功，它自动找到了DevC++下的gcc.exe等编译器。
（3）在build3目录执行make，就能够编译生成Turorial.exe了。
D:/Projects/Lab/testngpp/cm...
Getting key with maximum value in dictionary?
...
You can use operator.itemgetter for that:
import operator
stats = {'a':1000, 'b':3000, 'c': 100}
max(stats.iteritems(), key=operator.itemgetter(1))[0]
And instead of building a new list in memory use stats.iteritems(). The key parameter to the max() function is a function that computes a key th...
From inside of a Docker container, how do I connect to the localhost of the machine?
...
30 Answers
30
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Current time formatting with Javascript
...ar() - Returns the 4-digit year
getMonth() - Returns a zero-based integer (0-11) representing the month of the year.
getDate() - Returns the day of the month (1-31).
getDay() - Returns the day of the week (0-6). 0 is Sunday, 6 is Saturday.
getHours() - Returns the hour of the day (0-23).
getMinutes...
Connect to a locally built Jekyll Server using mobile devices in the LAN
..., a WEBrick server is set up and the site can be accessed from localhost:4000 on this particular PC.
2 Answers
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What's the simplest way to test whether a number is a power of 2 in C++?
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(n & (n - 1)) == 0 is best. However, note that it will incorrectly return true for n=0, so i...
java.net.ConnectException: localhost/127.0.0.1:8080 - Connection refused
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10 Answers
10
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Inline labels in Matplotlib
...e(np.int32)
# mask stuff outside plot
mask = (xy[:,0] >= 0) & (xy[:,0] < N) & (xy[:,1] >= 0) & (xy[:,1] < N)
xy = xy[mask]
# add to pop
for p in xy:
pop[l][tuple(p)] = 1.0
# find whitespace, nice place for label...
Pandas groupby: How to get a union of strings
..._csv(StringIO(data),sep='\s+')
In [5]: df
Out[5]:
A B C
0 1 0.749065 This
1 2 0.301084 is
2 3 0.463468 a
3 4 0.643961 random
4 1 0.866521 string
5 2 0.120737 !
In [6]: df.dtypes
Out[6]:
A int64
B float64
C object
dtype: object
When...
JavaScript function similar to Python range()
...ned') {
// one param defined
stop = start;
start = 0;
}
if (typeof step == 'undefined') {
step = 1;
}
if ((step > 0 && start >= stop) || (step < 0 && start <= stop)) {
return [];
}
var result = [];
for...