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Using bootstrap with bower
...s|css} files.
– 0x126
Apr 18 '16 at 10:53
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How big can a user agent string get?
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My database has 10,235 distinct user agent strings. I wanted to find the fastest hash algorithm that didn't produce any collisions. For my PHP environment I found md5 performed quickly at 2.3 seconds with no collisions. Interestingly I tr...
JSP tricks to make templating easier?
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answered Jul 15 '10 at 15:58
Will HartungWill Hartung
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“Unable to find manifest signing certificate in the certificate store” - even when add new key
...d enough for me.
– Parrotmaster
Mar 10 at 9:02
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How can I verify if one list is a subset of another?
...le, timeit.repeat('set(a)<set(b)', 'a = [1,3,5]; b = [1,3,5,7]', number=1000) and timeit.repeat('set(a).issubset(b)', 'a = [1,3,5]; b = [1,3,5,7]', number=1000)
– Yulan Liu
Nov 28 '14 at 16:50
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Find object in list that has attribute equal to some value (that meets any condition)
... other.value
import random
value = 5
test_list = [Test(random.randint(0,100)) for x in range(1000)]
if value in test_list:
print "i found it"
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Detecting 'stealth' web-crawlers
...e talking about these kinds of schemes who want to block anyone who tops 5-10 hits in a second, which may generate false positives on image-heavy pages (unless images are excluded from the tally) and will generate false positives when someone like me finds an interesting site that he wants to read a...
What are all possible pos tags of NLTK?
...oo, thanks!
– Phonebox
Jul 4 '15 at 10:38
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@phipsgabler if others are like me, I had wrong expec...
Best practices for exception management in Java or C# [closed]
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Brian RasmussenBrian Rasmussen
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Fastest way to check if a value exists in a list
...y zero entries in any of the time_method lists
Nls = [x for x in range(10000, 30000, 1000)]
for N in Nls:
a = [x for x in range(0, N)]
random.shuffle(a)
b = [x for x in range(0, N)]
random.shuffle(b)
c = [0 for x in range(0, N)]
time_method_in...