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AngularJS - $anchorScroll smooth/duration
...naudbreton/angular-smoothscroll
https://gist.github.com/justinmc/d72f38339e0c654437a2
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How do I declare and initialize an array in Java?
...s/api/java/util/stream/IntStream.html
int [] myIntArray = IntStream.range(0, 100).toArray(); // From 0 to 99
int [] myIntArray = IntStream.rangeClosed(0, 100).toArray(); // From 0 to 100
int [] myIntArray = IntStream.of(12,25,36,85,28,96,47).toArray(); // The order is preserved.
int [] myIntArray =...
how to change an element type using jquery
...re's one way you could do it with jQuery:
var attrs = { };
$.each($("b")[0].attributes, function(idx, attr) {
attrs[attr.nodeName] = attr.nodeValue;
});
$("b").replaceWith(function () {
return $("<h1 />", attrs).append($(this).contents());
});
Example: http://jsfiddle.net/yapHk/
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Google Map API v3 — set bounds and center
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answered Feb 5 '10 at 7:14
spencercoolyspencercooly
5,79822 gold badges2020 silver badges1515 bronze badges
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Multidimensional Array [][] vs [,] [duplicate]
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501
One is an array of arrays, and one is a 2d array. The former can be jagged, the latter is unif...
How to find controls in a repeater header or footer
...peater.
To find a control in the header:
lblControl = repeater1.Controls[0].Controls[0].FindControl("lblControl");
To find a control in the footer:
lblControl = repeater1.Controls[repeater1.Controls.Count - 1].Controls[0].FindControl("lblControl");
With extension methods
public static clas...
How do I programmatically get the GUID of an application in .net2.0
I need to access the assembly of my project in C# .NET2.0.
7 Answers
7
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Add leading zeroes to number in Java? [duplicate]
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1330
String.format (https://docs.oracle.com/javase/1.5.0/docs/api/java/util/Formatter.html#syntax)
I...
Colspan all columns
...en the HTML is being rendered)? w3schools mentions you can use colspan="0" , but it doesn't say exactly what browsers support that value (IE 6 is in our list to support).
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NodeJS: How to get the server's port?
...
});
// Only listen on $ node app.js
if (!module.parent) {
app.listen(3000);
console.log("Express server listening on port %d", app.address().port)
}
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