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How to parse a date? [duplicate]

...ormat that is set up with a different format. To parse your "Thu Jun 18 20:56:02 EDT 2009" date string you need a SimpleDateFormat like this (roughly): SimpleDateFormat parser=new SimpleDateFormat("EEE MMM d HH:mm:ss zzz yyyy"); Use this to parse the string into a Date, and then your other Sim...
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How do I declare a 2d array in C++ using new?

... answered Jun 1 '09 at 20:45 Mehrdad AfshariMehrdad Afshari 379k8383 gold badges822822 silver badges775775 bronze badges ...
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How to change a nullable column to not nullable in a Rails migration?

... 208 If you do it in a migration then you could probably do it like this: # Make sure no null valu...
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SVG gradient using CSS

... } <svg width="100" height="50" version="1.1" xmlns="http://www.w3.org/2000/svg"> <style type="text/css"> rect{fill:url(#MyGradient)} </style> <defs> <linearGradient id="MyGradient"> <stop offset="5%" stop-color="#F6...
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What is Vim recording and how can it be disabled?

... answered Oct 6 '09 at 20:08 yogsotothyogsototh 12.4k11 gold badge1717 silver badges2121 bronze badges ...
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Repeating characters in VIM insert mode

... answered Feb 20 '11 at 0:04 Matteo RivaMatteo Riva 23k1111 gold badges6969 silver badges103103 bronze badges ...
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Hidden features of Python [closed]

...;> x = 5 >>> 1 < x < 10 True >>> 10 < x < 20 False >>> x < 10 < x*10 < 100 True >>> 10 > x <= 9 True >>> 5 == x > 4 True In case you're thinking it's doing 1 < x, which comes out as True, and then comparing True <...
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Calendar Recurring/Repeating Events - Best Storage Method

...meta_key meta_value 1 1 repeat_start 1299132000 2 1 repeat_interval_1 432000 With repeat_start being a date with no time as a unix timestamp, and repeat_interval an amount in seconds between intervals (432000 is 5 days). repeat_interval_1 goes wit...
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Array.Copy vs Buffer.BlockCopy

...hat both methods are roughly 3x faster than using Array.Clone(), and maybe 20x faster than copying it in a for loop. – Ken Smith Sep 20 '11 at 22:12 3 ...
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MySQL: how to get the difference between two timestamps in seconds

... and the TIME_TO_SEC() functions as follows: SELECT TIME_TO_SEC(TIMEDIFF('2010-08-20 12:01:00', '2010-08-20 12:00:00')) diff; +------+ | diff | +------+ | 60 | +------+ 1 row in set (0.00 sec) You could also use the UNIX_TIMESTAMP() function as @Amber suggested in an other answer: SELECT UNIX_...