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SublimeText encloses lines in white rectangles
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Looks like you have SublimeLinter installed. It highlights errors and warnings.
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One or more types required to compile a dynamic expression cannot be found. Are you missing referenc
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Mine was already referenced yet I still had this error. I had created a new ASP.Net MVC4 application in VS 2010. Stumped, I removed and readded it, and the error went away. Cleaning/Rebuilding did not help.
– Paul
Mar 22 '13 at 21:5...
PHP - Debugging Curl
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$result = curl_exec($handle);
if ($result === FALSE) {
printf("cUrl error (#%d): %s<br>\n", curl_errno($handle),
htmlspecialchars(curl_error($handle)));
}
rewind($verbose);
$verboseLog = stream_get_contents($verbose);
echo "Verbose information:\n<pre>", htmlspecialcha...
PHP cURL HTTP CODE return 0
...$httpCode != 200 ){
echo "Return code is {$httpCode} \n"
.curl_error($ch);
} else {
echo "<pre>".htmlspecialchars($response)."</pre>";
}
curl_close($ch);
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Fatal error: Class 'ZipArchive' not found in
...but when I try to run the script to create the zip file it gives the fatal error
19 Answers
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Error CS1705: “which has a higher version than referenced assembly”
...nto this for a bit now and haven't gotten it resolved. I get the following error message:
20 Answers
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Git: can't undo local changes (error: path … is unmerged)
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Typical error when trying a checkout in the midst of a merge: $ git co path/to/file =result=> error: path 'path/to/file' is unmerged => so, first run: $ git reset path/to/file, and then the git checkout path/to/file should ...
Eclipse : An error occurred while filtering resources
I am building a Spring MVC project, and Eclipse is throwing this error (see screenshot). My pom.xml is:
1 Answer
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error LNK2019: 无法解析的外部符号 __imp__PlaySoundW@12，该符号在函数 \...
error LNK2019: 无法解析的外部符号 __imp__PlaySoundW@12，该符号在函数 "long __stdcall WndProc(struct HWND__ *,unsigned int,unsigned int,long)" (?WndProc@@YGJPAUHWND__@@IIJ@Z) 中被引用#include <mmsystem.h>#pragma comment(lib, "WINMM.LIB")
#include <mmsystem.h>
#pragma comm...
error C2664: “find_char”: 不能将参数 1 从“const char [14]”转换为“...
error C2664: “find_char”: 不能将参数 1 从“const char [14]”转换为“std::string &出错代码：#include <iostream>#include <string>using std::cout;using std::endl;using std::string; const引用形参举例 非const...出错代码：
#include <iostream>
#include <string>
using...