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Position of least significant bit that is set
... position of the least significant bit that is set in an integer, e.g. for 0x0FF0 it would be 4.
22 Answers
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Convert an image to grayscale in HTML/CSS
.../* Disable grayscale on hover */
img:hover {
-webkit-filter: grayscale(0);
filter: none;
}
<img src="http://lorempixel.com/400/200/">
What about Internet Explorer 10?
You can use a polyfill like gray.
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Given an array of numbers, return array of products of all other numbers (no division)
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260
An explanation of polygenelubricants method is:
The trick is to construct the arrays (in the c...
How do I cast a string to integer and have 0 in case of error in the cast with PostgreSQL?
...hould work:
SELECT CASE WHEN myfield~E'^\\d+$' THEN myfield::integer ELSE 0 END FROM mytable;
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CSS triangle custom border color
...th a 1px border (around the angled sides of the triangle) with color #CAD5E0. Is this possible? Here's what I have so far:
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Fetch frame count with ffmpeg
...below.
ffprobe: Query the container
ffprobe -v error -select_streams v:0 -show_entries stream=nb_frames -of default=nokey=1:noprint_wrappers=1 input.mp4
This is a fast method.
Not all formats (such as Matroska) will report the number of frames resulting in the output of N/A. See the other met...
How do I get indices of N maximum values in a NumPy array?
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edited Aug 2 '11 at 10:45
answered Aug 2 '11 at 10:32
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How to debug a GLSL shader?
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answered Mar 24 '10 at 17:14
Mr. BernaMr. Berna
10.1k11 gold badge3737 silver badges4141 bronze badges
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Find the max of two or more columns with pandas
...df = pd.DataFrame({"A": [1,2,3], "B": [-2, 8, 1]})
>>> df
A B
0 1 -2
1 2 8
2 3 1
>>> df[["A", "B"]]
A B
0 1 -2
1 2 8
2 3 1
>>> df[["A", "B"]].max(axis=1)
0 1
1 8
2 3
and so:
>>> df["C"] = df[["A", "B"]].max(axis=1)
>>> df
...
Two-dimensional array in Swift
...Int]] = []
OR if you need an array of predefined size (as mentioned by @0x7fffffff in comments):
// 2 dimensional array of arrays of Ints set to 0. Arrays size is 10x5
var arr = Array(count: 3, repeatedValue: Array(count: 2, repeatedValue: 0))
// ...and for Swift 3+:
var arr = Array(repeating: ...
