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How do you explicitly set a new property on `window` in TypeScript?
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edited Jun 15 '17 at 20:46
Luke
11.2k55 gold badges4040 silver badges7777 bronze badges
answered Oc...
How to add a “readonly” attribute to an ?
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answered Aug 20 '09 at 14:50
Christian C. SalvadóChristian C. Salvadó
688k171171 gold badges886886 silver badges826826 bronze badges
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Array.Copy vs Buffer.BlockCopy
...hat both methods are roughly 3x faster than using Array.Clone(), and maybe 20x faster than copying it in a for loop.
– Ken Smith
Sep 20 '11 at 22:12
3
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Converting numpy dtypes to native python types
...ime64(0, 'D').item()) # <class 'datetime.date'>
type(np.datetime64('2001-01-01 00:00:00').item()) # <class 'datetime.datetime'>
type(np.timedelta64(0, 'D').item()) # <class 'datetime.timedelta'>
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(Another method is np.asscalar(val), however it is deprecated since NumPy 1.16)...
Why 0 is true but false is 1 in the shell?
...more well known)?
– Guillaume86
Dec 20 '11 at 17:46
1
Assuming there is a boolean to int conversi...
How to check that an element is in a std::set?
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edited Mar 20 at 8:24
Jarvis
3,51533 gold badges1919 silver badges4242 bronze badges
answ...
Can I convert a C# string value to an escaped string literal
...iterals?
– rookie1024
Mar 27 '16 at 20:35
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show 7 more comments
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How to calculate md5 hash of a file using javascript
...generally unable to read files from the local filesystem.
I wrote that in 2009. So what about new browsers?
With a browser that supports the FileAPI, you *can * read the contents of a file - the user has to have selected it, either with an <input> element or drag-and-drop. As of Jan 2013, he...
MySQL: how to get the difference between two timestamps in seconds
... and the TIME_TO_SEC() functions as follows:
SELECT TIME_TO_SEC(TIMEDIFF('2010-08-20 12:01:00', '2010-08-20 12:00:00')) diff;
+------+
| diff |
+------+
| 60 |
+------+
1 row in set (0.00 sec)
You could also use the UNIX_TIMESTAMP() function as @Amber suggested in an other answer:
SELECT UNIX_...
SQL SERVER: Get total days between two dates
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PRINT DATEDIFF(DAY, '1/1/2011', '3/1/2011') will give you what you're after.
This gives the number of times the midnight boundary is crossed between the two dates. You may decide to need to add one to this if you're including both dates in the coun...