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How to get the response of XMLHttpRequest?
...like to know how to use XMLHttpRequest to load the content of a remote URL and have the HTML of the accessed site stored in a JS variable.
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What do two question marks together mean in C#?
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It's the null coalescing operator, and quite like the ternary (immediate-if) operator. See also ?? Operator - MSDN.
FormsAuth = formsAuth ?? new FormsAuthenticationWrapper();
expands to:
FormsAuth = formsAuth != null ? formsAuth : new FormsAuthenticationWr...
UPDATE multiple tables in MySQL using LEFT JOIN
I have two tables, and want to update fields in T1 for all rows in a LEFT JOIN.
5 Answers
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how to check redis instance version?
...urrently running version though. I had upgraded a server to 3.2.8 via yum, and this command showed the new version, but the server needed to be restarted manually to launch the new version, whereas INFO correctly reported the old version.
– X-Cubed
Apr 13 '17 a...
How do I find the stack trace in Visual Studio?
... would be nice for it to show the callers of the objects that throws an unhandled exception. Is there a hidden option to make it useful? Perhaps you can expand on your answer to provide examples.
– James
Jan 16 '15 at 16:43
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Get decimal portion of a number with JavaScript
I have float numbers like 3.2 and 1.6 .
22 Answers
22
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Django - limiting query results
I want to take the last 10 instances of a model and have this code:
5 Answers
5
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KnockOutJS - Multiple ViewModels in a single View
I'm thinking that my application is getting quite large now, too large to handle each View with a single ViewModel.
5 Answe...
Nested rows with bootstrap grid system?
...t you should really read the entire docs section on the grid so you understand how to leverage this powerful feature
<div class="container">
<div class="row">
<div class="col big-box">
image
</div>
<div class="col">
<div class="row">
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Repeat Character N Times
...s out that according to this jsperf, it appears that it's faster in Safari and Chrome (but not Firefox) to repeat a character multiple times by simply appending using a for loop (although a bit less concise).
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