大约有 46,000 项符合查询结果（耗时：0.0433秒） [XML]
Command-line Tool to find Java Heap Size and Memory Used (Linux)?
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edited Feb 1 '17 at 20:03
cybersoft
1,2631111 silver badges2525 bronze badges
answered Oct 9 '12 at...
How to handle exceptions in a list comprehensions?
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101
There is no built-in expression in Python that lets you ignore an exception (or return alternat...
How can I round to whole numbers in JavaScript?
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edited Aug 6 '11 at 16:10
Jeremy
21k44 gold badges6161 silver badges7777 bronze badges
answered Aug 6 ...
What function is to replace a substring from a string in C?
...| !rep)
return NULL;
len_rep = strlen(rep);
if (len_rep == 0)
return NULL; // empty rep causes infinite loop during count
if (!with)
with = "";
len_with = strlen(with);
// count the number of replacements needed
ins = orig;
for (count = 0; tmp = s...
Applying function with multiple arguments to create a new pandas column
...n:
>>> import numpy as np
>>> df = pd.DataFrame({"A": [10,20,30], "B": [20, 30, 10]})
>>> df['new_column'] = np.multiply(df['A'], df['B'])
>>> df
A B new_column
0 10 20 200
1 20 30 600
2 30 10 300
or vectorize arbitrary func...
Multiple inputs with same name through POST in php
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220
Change the names of your inputs:
<input name="xyz[]" value="Lorem" />
<input name="xyz...
Passing a URL with brackets to curl
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edited Jul 2 '19 at 20:14
moveson
4,45011 gold badge99 silver badges3131 bronze badges
answered Nov...
Best way to test if a generic type is a string? (C#)
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answered Aug 28 '08 at 2:08
Matt HamiltonMatt Hamilton
183k5959 gold badges376376 silver badges317317 bronze badges
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How to get the caret column (not pixels) position in a textarea, in characters, from the start?
...return node.selectionStart;
} else if (!document.selection) {
return 0;
}
var c = "\001",
sel = document.selection.createRange(),
dul = sel.duplicate(),
len = 0;
dul.moveToElementText(node);
sel.text = c;
len = dul.text.indexOf(c);
sel.moveStart('character',-1);...
How do you add an array to another array in Ruby and not end up with a multi-dimensional result?
...note the asterisk, and that a2 is the receiver
or splice:
a1[a1.length, 0] = a2
a1[a1.length..0] = a2
a1.insert(a1.length, *a2)
or append and flatten:
(a1 << a2).flatten! # a call to #flatten instead would return a new array
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