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How to use JavaScript variables in jQuery selectors?
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var name = this.name;
$("input[name=" + name + "]").hide();
OR you can do something like this.
var id = this.id;
$('#' + id).hide();
OR you can give some effect also.
$("#" + this.id).slideUp();
If you want to remove the entire element permanently form the page.
$("#" ...
How to map a composite key with JPA and Hibernate?
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To map a composite key, you can use the EmbeddedId or the IdClass annotations. I know this question is not strictly about JPA but the rules defined by the specification also applies. So here they are:
2.1.4 Primary Keys and Entity Identity
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A composite pri...
How to get Resource Name from Resource id
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to get string like radio1:
getResources().getResourceEntryName(int resid);
to get string like com.sample.app:id/radio1:
getResources().getResourceName(int resid);
In Kotlin Now :
val name = v.context.resources.getResourceEntryName(v.id)
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Check if a dialog is displayed with Espresso
I'm trying to write some tests with the new android-test-kit (Espresso) . But I can't find any information on how to check if a dialog is displayed and perform some actions on it (like clicking the positive and negative buttons, e.t.c.). Note that a dialog may be also displayed by a WebView , no...
How to create id with AUTO_INCREMENT on Oracle?
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There is no such thing as "auto_increment" or "identity" columns in Oracle as of Oracle 11g. However, you can model it easily with a sequence and a trigger:
Table definition:
CREATE TABLE departments (
ID NUMBER(10) NOT NULL,
DESCRIPTION VARCHAR2(50) ...
Convert Django Model object to dict with all of the fields intact
... one convert a Django Model object to a dict with all of its fields? All ideally includes foreign keys and fields with editable=False .
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What can , and be used for?
... parameters
The <f:viewParam> manages the setting, conversion and validation of GET parameters. It's like the <h:inputText>, but then for GET parameters.
The following example
<f:metadata>
<f:viewParam name="id" value="#{bean.id}" />
</f:metadata>
does basically th...
An App ID with Identifier '' is not available. Please enter a different string
I am trying to add a new APP ID to prepare for App Store submission and got the following error under the bundle ID I provided.
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How do I get the “id” after INSERT into MySQL database with Python?
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Use cursor.lastrowid to get the last row ID inserted on the cursor object, or connection.insert_id() to get the ID from the last insert on that connection.
share
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SELECT DISTINCT on one column
...r greater, you can use a CTE with ROW_NUMBER():
SELECT *
FROM (SELECT ID, SKU, Product,
ROW_NUMBER() OVER (PARTITION BY PRODUCT ORDER BY ID) AS RowNumber
FROM MyTable
WHERE SKU LIKE 'FOO%') AS a
WHERE a.RowNumber = 1
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