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How to get the index of a maximum element in a numpy array along one axis
I have a 2 dimensional NumPy array. I know how to get the maximum values over axes:
4 Answers
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Print commit message of a given commit in git
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edited Jul 28 '10 at 20:53
answered Jul 28 '10 at 20:47
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Gradient of n colors ranging from color 1 and color 2
I often work with ggplot2 that makes gradients nice ( click here for an example ). I have a need to work in base and I think scales can be used there to create color gradients as well but I'm severely off the mark on how. The basic goal is generate a palette of n colors that ranges from x colo...
How do you pass arguments to define_method?
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edited Sep 18 '08 at 3:12
answered Sep 18 '08 at 3:06
Kev...
Join a list of strings in python and wrap each string in quotation marks
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answered Aug 17 '12 at 14:28
jamylakjamylak
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How do I install an old version of Django on virtualenv?
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There was never a Django 1.0.7. The 1.0 series only went up to 1.0.4. You can see all the releas...
Python's “in” set operator
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answered Jan 2 '12 at 21:14
Ignacio Vazquez-AbramsIgnacio Vazquez-Abrams
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Select statement to find duplicates on certain fields
...lds for which there are multiple records, you can use..
select field1,field2,field3, count(*)
from table_name
group by field1,field2,field3
having count(*) > 1
Check this link for more information on how to delete the rows.
http://support.microsoft.com/kb/139444
There should be a criterion...
Getting and removing the first character of a string
I would like to do some 2-dimensional walks using strings of characters by assigning different values to each character. I was planning to 'pop' the first character of a string, use it, and repeat for the rest of the string.
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how to calculate binary search complexity
...rer as informal ones:
The question is, how many times can you divide N by 2 until you have 1? This is essentially saying, do a binary search (half the elements) until you found it. In a formula this would be this:
1 = N / 2x
multiply by 2x:
2x = N
now do the log2:
log2(2x) = l...