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How do I select a merge strategy for a git rebase?

... 236 You can use this with Git v1.7.3 or later versions. git rebase --strategy-option theirs ${bra...
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How to create an object for a Django model with a many to many field?

... 248 You cannot create m2m relations from unsaved objects. If you have the pks, try this: sample_o...
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How to match a String against string literals in Rust?

... => println!("0"), "b" => println!("1"), "c" => println!("2"), _ => println!("something else!"), } There's also an as_str method as of Rust 1.7.0: match stringthing.as_str() { "a" => println!("0"), "b" => println!("1"), "c" => println!("2"), _ =&gt...
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in_array multiple values

... 200 Intersect the targets with the haystack and make sure the intersection is precisely equal to t...
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Integrate ZXing in Android Studio

... 234 I was integrating ZXING into an Android application and there were no good sources for the inp...
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Enable 'xp_cmdshell' SQL Server

... answered Feb 27 '11 at 4:43 Pero P.Pero P. 20.9k66 gold badges5252 silver badges7878 bronze badges ...
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Join a list of strings in python and wrap each string in quotation marks

... answered Aug 17 '12 at 14:28 jamylakjamylak 104k2222 gold badges206206 silver badges215215 bronze badges ...
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Adding a new array element to a JSON object

... 242 JSON is just a notation; to make the change you want parse it so you can apply the changes to ...
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Strange, unexpected behavior (disappearing/changing values) when using Hash default value, e.g. Hash

...s in the array, despite h[1] still giving us a value? Here’s a hint: h[42] #=> ["a", "b"] The array returned by each [] call is just the default value, which we’ve been mutating all this time so now contains our new values. Since << doesn’t assign to the hash (there can never be a...
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how to calculate binary search complexity

...rer as informal ones: The question is, how many times can you divide N by 2 until you have 1? This is essentially saying, do a binary search (half the elements) until you found it. In a formula this would be this: 1 = N / 2x multiply by 2x: 2x = N now do the log2: log2(2x)    = l...