大约有 43,000 项符合查询结果（耗时：0.0511秒） [XML]
Encode String to UTF-8
I have a String with a "ñ" character and I have some problems with it. I need to encode this String to UTF-8 encoding. I have tried it by this way, but it doesn't work:
...
How to change options of with jQuery?
Suppose a list of options is available, how do you update the <select> with new <option> s?
9 Answers
...
Android - Set max length of logcat messages
...e { Log.v(TAG, sb); } to also print the log when the message is <= 4000 chars long
– Bojan Radivojevic Bomber
Apr 26 '14 at 21:45
...
Select last row in MySQL
How can I SELECT the last row in a MySQL table?
10 Answers
10
...
Best way to create enum of strings?
...
@Mark, true, it can't handle any character. If the OP just wants a single char, this solution is more straight forward than The Elite Gentleman suggestion. But indeed: if the range of characters exceeds the ones a valid Java identifier can have, this is a no...
Use 'class' or 'typename' for template parameters? [duplicate]
...s expected T will always be a class, with "typename" if other types (int, char* whatever) may be expected. Consider it a usage hint.
share
|
improve this answer
|
follow
...
SQLiteDatabase.query method
...
tableColumns
null for all columns as in SELECT * FROM ...
new String[] { "column1", "column2", ... } for specific columns as in SELECT column1, column2 FROM ... - you can also put complex expressions here:
new String[] { "(SELECT max(column1) FROM table1) AS max" }...
Get list of all tables in Oracle?
...
SELECT owner, table_name
FROM dba_tables
This is assuming that you have access to the DBA_TABLES data dictionary view. If you do not have those privileges but need them, you can request that the DBA explicitly grants you...
SELECT * FROM X WHERE id IN (…) with Dapper ORM
...
Dapper supports this directly. For example...
string sql = "SELECT * FROM SomeTable WHERE id IN @ids"
var results = conn.Query(sql, new { ids = new[] { 1, 2, 3, 4, 5 }});
share
|
imp...
How do I find duplicate values in a table in Oracle?
...then use a HAVING clause to find values that appear greater than one time.
SELECT column_name, COUNT(column_name)
FROM table_name
GROUP BY column_name
HAVING COUNT(column_name) > 1;
share
|
impr...