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100% width Twitter Bootstrap 3 template

...lable any longer. I have no idea how to achieve that layout with bootstrap 3. I am using the Geometry PSD template from themeforest, the link here if you want to see the layout : http://themeforest.net/item/geometry-design-for-geolocation-social-networkr/4752268 ...
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How to initialize all members of an array to the same value in Swift?

...ue like this: With old Swift version: var threeDoubles = [Double](count: 3, repeatedValue: 0.0) Since Swift 3.0: var threeDoubles = [Double](repeating: 0.0, count: 3) which would give: [0.0, 0.0, 0.0] share ...
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python list by value not by reference [duplicate]

... answered Jan 5 '12 at 14:30 phihagphihag 239k6060 gold badges406406 silver badges444444 bronze badges ...
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How can I open multiple files using “with open” in Python?

... As of Python 2.7 (or 3.1 respectively) you can write with open('a', 'w') as a, open('b', 'w') as b: do_something() In earlier versions of Python, you can sometimes use contextlib.nested() to nest context managers. This won't work as expe...
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How to map with index in Ruby?

... answered Jan 15 '11 at 1:37 sepp2ksepp2k 331k4747 gold badges635635 silver badges652652 bronze badges ...
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How do I detect if Python is running as a 64-bit application? [duplicate]

...k with the windows registry. Depending on whether you're running python as 32-bit or 64-bit, the key value will be different. How do I detect if Python is running as a 64-bit application as opposed to a 32-bit application? ...
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How to pip or easy_install tkinter on Windows

... 38 Well I can see two solutions here: 1) Follow the Docs-Tkinter install for Python (for Windows)...
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Way to get number of digits in an int?

... 30 Answers 30 Active ...
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How many String objects will be created when using a plus sign?

... String one = "1"; String two = "2"; String result = one + two + "34"; Console.Out.WriteLine(result); } then the compiler seems to emit the code using String.Concat as @Joachim answered (+1 to him btw). If you define them as constants, e.g.: const String one = "1"; const String two ...
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Regex how to match an optional character

... You could improve your regex to ^([0-9]{5})+\s+([A-Z]?)\s+([A-Z])([0-9]{3})([0-9]{3})([A-Z]{3})([A-Z]{3})\s+([A-Z])[0-9]{3}([0-9]{4})([0-9]{2})([0-9]{2}) And, since in most regex dialects, \d is the same as [0-9]: ^(\d{5})+\s+([A-Z]?)\s+([A-Z])(\d{3})(\d{3})([A-Z]{3})([A-Z]{3})\s+([A-Z])\d{3}(...