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100% width Twitter Bootstrap 3 template
...lable any longer. I have no idea how to achieve that layout with bootstrap 3. I am using the Geometry PSD template from themeforest, the link here if you want to see the layout : http://themeforest.net/item/geometry-design-for-geolocation-social-networkr/4752268
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How to initialize all members of an array to the same value in Swift?
...ue like this:
With old Swift version:
var threeDoubles = [Double](count: 3, repeatedValue: 0.0)
Since Swift 3.0:
var threeDoubles = [Double](repeating: 0.0, count: 3)
which would give:
[0.0, 0.0, 0.0]
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python list by value not by reference [duplicate]
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answered Jan 5 '12 at 14:30
phihagphihag
239k6060 gold badges406406 silver badges444444 bronze badges
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How can I open multiple files using “with open” in Python?
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As of Python 2.7 (or 3.1 respectively) you can write
with open('a', 'w') as a, open('b', 'w') as b:
do_something()
In earlier versions of Python, you can sometimes use
contextlib.nested() to nest context managers. This won't work as expe...
How to map with index in Ruby?
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answered Jan 15 '11 at 1:37
sepp2ksepp2k
331k4747 gold badges635635 silver badges652652 bronze badges
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How do I detect if Python is running as a 64-bit application? [duplicate]
...k with the windows registry. Depending on whether you're running python as 32-bit or 64-bit, the key value will be different. How do I detect if Python is running as a 64-bit application as opposed to a 32-bit application?
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How to pip or easy_install tkinter on Windows
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38
Well I can see two solutions here:
1) Follow the Docs-Tkinter install for Python (for Windows)...
Way to get number of digits in an int?
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30 Answers
30
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How many String objects will be created when using a plus sign?
... String one = "1";
String two = "2";
String result = one + two + "34";
Console.Out.WriteLine(result);
}
then the compiler seems to emit the code using String.Concat as @Joachim answered (+1 to him btw).
If you define them as constants, e.g.:
const String one = "1";
const String two ...
Regex how to match an optional character
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You could improve your regex to
^([0-9]{5})+\s+([A-Z]?)\s+([A-Z])([0-9]{3})([0-9]{3})([A-Z]{3})([A-Z]{3})\s+([A-Z])[0-9]{3}([0-9]{4})([0-9]{2})([0-9]{2})
And, since in most regex dialects, \d is the same as [0-9]:
^(\d{5})+\s+([A-Z]?)\s+([A-Z])(\d{3})(\d{3})([A-Z]{3})([A-Z]{3})\s+([A-Z])\d{3}(...