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“Uncaught TypeError: Illegal invocation” in Chrome

When I use requestAnimationFrame to do some native supported animation with below code: 3 Answers ...
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Must qualify the allocation with an enclosing instance of type GeoLocation

I am getting this error as- 6 Answers 6 ...
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What's the use/meaning of the @ character in variable names in C#?

...ad a member variable with the name "params". Obviously this is a reserved word in C# so you can't have a class with a member variable with the name "params". The proxy object that was generated contained a property that looked like this: ...
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What's wrong with foreign keys?

...ring Joel Spolsky mention in podcast 014 that he'd barely ever used a foreign key (if I remember correctly). However, to me they seem pretty vital to avoid duplication and subsequent data integrity problems throughout your database. ...
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Is there a way to use shell_exec without waiting for the command to complete?

...adding. "> /dev/null 2>/dev/null &" shell_exec('php measurePerformance.php 47 844 email@yahoo.com > /dev/null 2>/dev/null &'); Note this also gets rid of the stdio and stderr. share | ...
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How to delete a remote tag?

...ou just need to push an 'empty' reference to the remote tag name: git push origin :tagname Or, more expressively, use the --delete option (or -d if your git version is older than 1.8.0): git push --delete origin tagname Note that git has tag namespace and branch namespace so you may use the same n...
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Node.js: what is ENOSPC error and how to solve?

I have a problem with Node.js and uploading files to server. For uploading files to server I use this plugin . When starting file upload to the server, Node.js process crashed and show error: ...
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How do I get the key at a specific index from a Dictionary in Swift?

...e dictionary's startIndex by the integer that you wanted to subscript by, for example: let intIndex = 1 // where intIndex < myDictionary.count let index = myDictionary.index(myDictionary.startIndex, offsetBy: intIndex) myDictionary.keys[index] Another possible solution would be to initialize a...
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What is the simplest and most robust way to get the user's current location on Android?

...e LocationManager API on Android seems like it's a bit of a pain to use for an application that only needs an occasional and rough approximation of the user's location. ...
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Breaking out of nested loops [duplicate]

...t been suggested, but also rejected. I don't think there is another way, short of repeating the test or re-organizing the code. It is sometimes a bit annoying. In the rejection message, Mr van Rossum mentions using return, which is really sensible and something I need to remember personally. :) ...