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How to remove convexity defects in a Sudoku square?
I was doing a fun project: Solving a Sudoku from an input image using OpenCV (as in Google goggles etc). And I have completed the task, but at the end I found a little problem for which I came here.
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How to insert a row in an HTML table body in JavaScript
I have an HTML table with a header and a footer:
9 Answers
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How can I scale an image in a CSS sprite
In this article, http://css-tricks.com/css-sprites/ , it talks about how can I crop off a smaller image from 1 bigger image. Can you please tell me if it is possible/how I can crop off a smaller image and then scale the cropped off region before I lay it out?
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How to identify numpy types in python?
How can one reliably determine if an object has a numpy type?
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HTML5: Slider with two inputs possible?
Is it possible to make a HTML5 slider with two input values, for example to select a price range? If so, how can it be done?
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Cost of exception handlers in Python
In another question , the accepted answer suggested replacing a (very cheap) if statement in Python code with a try/except block to improve performance.
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What do the numbers in a version typically represent (i.e. v1.9.0.1)?
Maybe this is a silly question, but I've always assumed each number delineated by a period represented a single component of the software. If that's true, do they ever represent something different? I'd like to start assigning versions to the different builds of my software, but I'm not really sure...
How to access the local Django webserver from outside world
I followed the instructions here to run Django using the built-in webserver and was able to successfully run it using python manage.py runserver . If I access 127.0.0.1:port locally from the webserver, I get the Django page indicating it worked.
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How to compare versions in Ruby?
How to write a piece of code to compare some versions strings and get the newest?
8 Answers
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UITableView + Add content offset at top
I need to add some blank space to the top of my UITableView that does not affect the size of the content area. Shifting the content down or adding a blank cell is NOT what I want to do. Instead I just want an offset.
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