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Django fix Admin plural

... answered Apr 6 '10 at 19:54 Andriy DrozdyukAndriy Drozdyuk 47.4k4343 gold badges143143 silver badges252252 bronze badges ...
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How to elegantly check if a number is within a range?

... There are a lot of options: int x = 30; if (Enumerable.Range(1,100).Contains(x)) //true if (x >= 1 && x <= 100) //true Also, check out this SO post for regex options. share | ...
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HTML/Javascript change div content

... answered Mar 31 '10 at 15:19 SyntacticSyntactic 9,05511 gold badge2121 silver badges2525 bronze badges ...
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Strange \n in base64 encoded string in Ruby

... answered Apr 12 '10 at 9:38 Christoffer HammarströmChristoffer Hammarström 23.2k44 gold badges4343 silver badges5353 bronze badges ...
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Unique (non-repeating) random numbers in O(1)?

I'd like to generate unique random numbers between 0 and 1000 that never repeat (i.e. 6 doesn't show up twice), but that doesn't resort to something like an O(N) search of previous values to do it. Is this possible? ...
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Add new item count to icon on button - Android

...android" android:shape="rectangle"> <corners android:radius="10dip"/> <solid android:color="#F00" /> <stroke android:width="2dip" android:color="#FFF" /> <padding android:left="5dip" android:right="5dip" android:top="5dip" android:bot...
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How to get MD5 sum of a string using python?

... answered Mar 14 '11 at 10:43 IkkeIkke 86.9k2323 gold badges9090 silver badges117117 bronze badges ...
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Browser support for URLs beginning with double slash

... answered Mar 9 '12 at 10:18 oezioezi 46.5k1010 gold badges9090 silver badges113113 bronze badges ...
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What is the maximum value for an int32?

... My mnemonic: 2^10 is very near to 1000, so 2^(3*10) is 1000^3 or about 1 billion. One of the 32 bits is used for sign, so the max value is really only 2^31, which is about twice the amount you get for 2^(3*10): 2 billion. ...
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Easiest way to rename a model using Django/South?

... answered May 24 '10 at 18:07 LeopdLeopd 36.3k2828 gold badges114114 silver badges154154 bronze badges ...