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How do I horizontally center a span element inside a div
...fff;
display: inline-block;
/* float:left; remove */
margin: 10px 10px 0 0;
padding: 5px 10px
}
http://jsfiddle.net/Adrift/cePe3/
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Move an item inside a list?
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answered Jul 3 '10 at 23:15
David ZDavid Z
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Percentage width in a RelativeLayout
...es to define your layout.
In the following example, the left button uses 70% of the space, and the right button 30%.
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="horizontal">
<Button
android:text="lef...
How to strike through obliquely with css
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190
There is a hacky way to do this, using the :before pseudo element. You give the :before a border...
Calling clojure from java
...intln (str "(binomial 5 3): " (binomial 5 3)))
(println (str "(binomial 10042 111): " (binomial 10042 111)))
)
If you run it, you should see something like:
(binomial 5 3): 10
(binomial 10042 111): 49068389575068144946633777...
And here's a Java program that calls the -binomial function in th...
html5 - canvas element - Multiple layers
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<div style="position: relative;">
<canvas id="layer1" width="100" height="100"
style="position: absolute; left: 0; top: 0; z-index: 0;"></canvas>
<canvas id="layer2" width="100" height="100"
style="position: absolute; left: 0; top: 0; z-index: 1;"></canvas>...
How do I add a tool tip to a span element?
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edited Jun 28 '09 at 19:41
answered Jun 28 '09 at 19:36
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Converting an integer to a hexadecimal string in Ruby
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You can give to_s a base other than 10:
10.to_s(16) #=> "a"
Note that in ruby 2.4 FixNum and BigNum were unified in the Integer class.
If you are using an older ruby check the documentation of FixNum#to_s and BigNum#to_s
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What's Go's equivalent of argv[0]?
...t my own program's name at runtime? What's Go's equivalent of C/C++'s argv[0]? To me it is useful to generate the usage with the right name.
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How do I put double quotes in a string in vba?
... handle a quote.
Worksheets("Sheet1").Range("A1").Formula = "IF(Sheet1!A1=0,"""",Sheet1!A1)"
Some people like to use CHR(34)*:
Worksheets("Sheet1").Range("A1").Formula = "IF(Sheet1!A1=0," & CHR(34) & CHR(34) & ",Sheet1!A1)"
*Note: CHAR() is used as an Excel cell formula, e.g. wri...