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Replace duplicate spaces with a single space in T-SQL
...
Even tidier:
select string = replace(replace(replace(' select single spaces',' ','<>'),'><',''),'<>',' ')
Output:
select single spaces
...
How to extend an existing JavaScript array with another array, without creating a new array
...ed for "JavaScript array extend" and got here, you can very well use Array.concat.
var a = [1, 2, 3];
a = a.concat([5, 4, 3]);
Concat will return a copy the new array, as thread starter didn't want. But you might not care (certainly for most kind of uses this will be fine).
There's also some n...
node.js fs.readdir recursive directory search
... {
walk(file, function(err, res) {
results = results.concat(res);
if (!--pending) done(null, results);
});
} else {
results.push(file);
if (!--pending) done(null, results);
}
});
});
});
};
A serial loop wo...
Merging two arrays in .NET
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In C# 3.0 you can use LINQ's Concat method to accomplish this easily:
int[] front = { 1, 2, 3, 4 };
int[] back = { 5, 6, 7, 8 };
int[] combined = front.Concat(back).ToArray();
In C# 2.0 you don't have such a direct way, but Array.Copy is probably the ...
How to merge a list of lists with same type of items to a single list of items?
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Use the SelectMany extension method
list = listOfList.SelectMany(x => x).ToList();
share
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improve this answer
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Fastest way to flatten / un-flatten nested JSON objects
... Object.keys(obj).forEach(key => {
this.flatten(obj[key], prefix.concat(key), current)
})
} else {
current[prefix.join('.')] = obj
}
return current
}
Features and/or caveats
It only accepts JSON objects. So if you pass something like {a: () => {}} you might not get wh...
What is the purpose of “!” and “?” at the end of method names?
... Beware, this isn't always the case. For example, Ruby Array#concat docs.ruby-lang.org/en/2.0.0/Array.html#method-i-concat. Where you can get burnt badly is something like MyActiveRecordModel.column_names.concat(...). Instead you must clone it before doing the concat.
...
Count the number of occurrences of a string in a VARCHAR field?
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This should do the trick:
SELECT
title,
description,
ROUND (
(
LENGTH(description)
- LENGTH( REPLACE ( description, "value", "") )
) / LENGTH("value")
) AS count
FROM <tab...
String concatenation in Ruby
I am looking for a more elegant way of concatenating strings in Ruby.
16 Answers
16
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Is it possible to apply CSS to half of a character?
.../
overflow: hidden;
pointer-events: none; /* so the base char is selectable by mouse */
color: #f00; /* for demo purposes */
text-shadow: 2px -2px 0px #af0; /* for demo purposes */
}
.halfStyle:after { /* creates the right part */
display: block;
direction: rtl; /* ...