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How to add a new row to datagridview programmatically
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Lets say you have a datagridview that is not bound to a dataset and you want to programmatically populate new rows...
Here's how you do it.
// Create a new row first as it will include the columns you've created at design-time.
int rowId = dataGridView1.Rows.Add();
// Grab the new...
ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'db'
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You may need to set up a root account for your MySQL database:
In the terminal type:
mysqladmin -u root password 'root password goes here'
And then to invoke the MySQL client:
mysql -h localhost -u root -p
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How do I look inside a Python object?
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Python has a strong set of introspection features.
Take a look at the following built-in functions:
type()
dir()
id()
getattr()
hasattr()
globals()
locals()
callable()
type() and dir() are particularly useful for inspecting the type of an ...
滚动布局管理器拓展 - ScrollArrangementHandler · App Inventor 2 中文网
...动事件处理
when HorizontalScrollHandler1.ScrollChanged scrollX
do
set Label_Position.Text to "当前位置: " & scrollX
// 到达右端事件
when HorizontalScrollHandler1.ReachRightEnd
do
show notification "已到达最右端"
// 垂直滚动事件处理
when VerticalScrollHandler1.S...
Throw away local commits in Git
Due to some bad cherry-picking, my local Git repository is currently five commits ahead of the origin, and not in a good state. I want to get rid of all these commits and start over again.
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Rails - Could not find a JavaScript runtime?
I created a new Rails project using rails 3.1.0.rc4 on my local machine but when I try to start the server I get:
Could not find a JavaScript runtime. See here for a list of available runtimes. ( ExecJS::RuntimeUnavailable )
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Load image from resources area of project in C#
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The best thing is to add them as Image Resources in the Resources settings in the Project. Then you can get the image directly by doing Resources.myimage. This will get the image via a generated C# property.
If you just set the image as Embedded Resource you can get it with:
string name =...
“Invalid JSON primitive” in Ajax processing
...barvalue thus you get the error "Invalid JSON primitive: foo"
Try instead setting the data as string
$.ajax({
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data: "{'foo':'foovalue', 'bar':'barvalue'}", //note the additional quotation marks
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})
This way jQuery should leave the data alone and send the string as is to the se...
val() doesn't trigger change() in jQuery [duplicate]
...e input loses focus.
You can manually call the onchange event using after setting the value:
$("#mytext").change(); // someObject.onchange(); in standard JS
Alternatively, you can trigger the event using:
$("#mytext").trigger("change");
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Giving a border to an HTML table row,
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You can set border properties on a tr element, but according to the CSS 2.1 specification, such properties have no effect in the separated borders model, which tends to be the default in browsers. Ref.: 17.6.1 The separated borders m...
