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How can I read SMS messages from the device programmatically in Android?
...solver().query(Uri.parse("content://sms/inbox"), null, null, null, null);
if (cursor.moveToFirst()) { // must check the result to prevent exception
do {
String msgData = "";
for(int idx=0;idx<cursor.getColumnCount();idx++)
{
msgData += " " + cursor.getColumnNa...
How to escape JSON string?
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No problem, thanks for replying. I did this if it helps you: yourAnnoyingDoubleEncodedString.Replace("\\\\", "\\").Replace("\\\"", "\"");
– GP24
Feb 11 '16 at 15:24
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datetime.parse and making it work with a specific format
...ure of the operation - I'm still on .Net 1.1, so I often forget this one.
If you need to parse other formats, you can check out the Standard DateTime Format Strings.
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“Cannot update paths and switch to branch at the same time”
...re origin is fetched:
git fetch origin
Then:
git branch -avv
(to see if you do have fetched an origin/master branch)
Finally, use git switch instead of the confusing git checkout, with Git 2.23+ (August 2019).
git switch -c test --track origin/master
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What is the fastest/most efficient way to find the highest set bit (msb) in an integer in C?
If I have some integer n, and I want to know the position of the most significant bit (that is, if the least significant bit is on the right, I want to know the position of the furthest left bit that is a 1), what is the quickest/most efficient method of finding out?
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Store output of subprocess.Popen call in a string
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if you want to get error stream add stderr: p = subprocess.Popen(["ntpq", "-p"], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
– Timofey
May 27 '14 at 12:29
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node.js, socket.io with SSL
I'm trying to get socket.io running with my SSL certificate however, it will not connect.
9 Answers
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A more useful statusline in vim? [closed]
...change to your power line segments? could u update some default segment modification scripts? cheers
– Jerry Gao
May 8 '12 at 8:22
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Set value for particular cell in pandas DataFrame using index
...urns a new dataframe with a copy of the data, so
df.xs('C')['x']=10
modifies this new dataframe only.
df['x'] returns a view of the df dataframe, so
df['x']['C'] = 10
modifies df itself.
Warning: It is sometimes difficult to predict if an operation returns a copy or a view. For this reason...