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XAMPP - Port 80 in use by “Unable to open process” with PID 4! 12
...lso disable them.
Start Apache again with XAMPP :)
Link Ref: https://www.sitepoint.com/unblock-port-80-on-windows-run-apache/
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When should we call System.exit in Java
...ix shell script or windows cmd script, you might check this answer on this site
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Using .otf fonts on web browsers
I'm working on a website that requires font trials online, the fonts I have are all .otf
2 Answers
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ASP.NET Temporary files cleanup
...re also cases where the temp folder can be set via config for a machine or site specific using this:
<compilation tempDirectory="d:\MyTempPlace" />
I even have a funky setup at work where we don't run Admin by default, plus the IT guys have login scripts that set %temp% and I get temp files...
How to flatten nested objects with linq expression
...
ContactCompany = companyPerson.Company
}
)
Ref site I used: http://odetocode.com/blogs/scott/archive/2008/03/25/inner-outer-lets-all-join-together-with-linq.aspx
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How to profile methods in Scala?
... libraries for Scala that you can avail of.
Since the URLs on the linked site are likely to change, I am pasting the relevant content below.
SPerformance - Performance Testing framework aimed at automagically comparing performance tests and working inside Simple Build Tool.
scala-benchmarking-te...
Send Email Intent
...Gmail + Inbox suggested):
I got this solution from the Android Developers site.
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How do I comment on the Windows command line?
... I doubled the amount of knowledge in the world. FWIW, Rob van der Woude's site is a truly excellent one for batch file (and other) chicanery: robvanderwoude.com/batchfiles.php
– paxdiablo
Jun 8 '10 at 23:55
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How can I use a carriage return in a HTML tooltip?
I'm currently adding verbose tooltips to our site, and I'd like (without having to resort to a whizz-bang jQuery plugin, I know there are many!) to use carriage returns to format the tooltip.
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Django admin: How to display a field that is marked as editable=False' in the model?
...cond',)
class FooAdmin(admin.ModelAdmin):
form = CustomFooForm
admin.site.register(FooModel, FooAdmin)
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