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Can virtual functions have default parameters?

...e class' or a derived class' -- is determined by the static type used to make the call to the function. If you call through a base class object, pointer or reference, the default denoted in the base class is used. Conversely, if you call through a derived class object, pointer or reference the def...
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Is there a way to remove the separator line from a UITableView?

I'm looking for a way to completely remove the separator line in a UITableView when in the plain mode. This is done automatically in grouped, but this also changes the dimensions of the table in a way that is hard to measure. I have set the seperator line color to colorClear. But this does not compl...
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How do you get the length of a string?

... Artem BargerArtem Barger 37.8k99 gold badges5252 silver badges7878 bronze badges ...
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How to set a bitmap from resource

...s, is required. It is normally obtainable in any Context (and subclasses like Activity). share | improve this answer | follow | ...
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How to print an exception in Python?

How can I print the error/exception in my except: block? 8 Answers 8 ...
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Why is the minimalist, example Haskell quicksort not a “true” quicksort?

Haskell's website introduces a very attractive 5-line quicksort function , as seen below. 11 Answers ...
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How to deal with persistent storage (e.g. databases) in Docker

How do people deal with persistent storage for your Docker containers? 14 Answers 14 ...
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Rails: How to change the title of a page?

... In your views do something like this: <% content_for :title, "Title for specific page" %> <!-- or --> <h1><%= content_for(:title, "Title for specific page") %></h1> The following goes in the layout file: <head> &...
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When should I make explicit use of the `this` pointer?

...t;int> b; b.foo(); } If you omit this->, the compiler does not know how to treat i, since it may or may not exist in all instantiations of A. In order to tell it that i is indeed a member of A<T>, for any T, the this-> prefix is required. Note: it is possible to still omit this...
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Get name of property as a string

...re: Retrieving Property name from lambda expression you can do something like this: RemoteMgr.ExposeProperty(() => SomeClass.SomeProperty) public class SomeClass { public static string SomeProperty { get { return "Foo"; } } } public class RemoteMgr { public static void ...