大约有 3,621 项符合查询结果（耗时：0.0173秒） [XML]
Detecting touch screen devices with Javascript
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Found testing for window.Touch didn't work on android but this does:
function is_touch_device() {
return !!('ontouchstart' in window);
}
See article: What's the best way to detect a 'touch screen' device using JavaScript?
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String contains - ignore case [duplicate]
... org.apache.commons.lang3.StringUtils this package not available in android
– Rahul Sonone
Jun 9 '16 at 11:21
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keytool error :java.io.IoException:Incorrect AVA format
I am new to Android development; when I have been trying to sign the application I have got the following error. Can anyone help me on this issue?
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Set value of textarea in jQuery
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On android .val and .html didn't work.
$('#id').text("some value")
did the job.
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Finishing current activity from a fragment
...ment in my opinion. Instead, I would use the guide here: http://developer.android.com/training/basics/fragments/communicating.html
Have the Fragment define an interface which the Activity must implement. Make a call up to the Activity, then let the Activity decide what to do with the information....
How to implement the Java comparable interface?
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In Android it requires API 19
– Hamzeh Soboh
Mar 30 '17 at 14:16
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How to prevent open last projects when intellij idea start
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Usefull for both intelij and android studio. Thanks!
– Andrew
Jul 25 '18 at 14:32
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Display current time in 12 hour format with AM/PM
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@akashbs For more info check these docs: developer.android.com/reference/java/text/SimpleDateFormat
– Tamim Attafi
Dec 30 '19 at 15:14
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Java 8 Iterable.forEach() vs foreach loop
...ection<E>{
private enum OperatingSystem{
LINUX, WINDOWS, ANDROID
}
private OperatingSystem operatingSystem = OperatingSystem.WINDOWS;
private int numberOfCores = Runtime.getRuntime().availableProcessors();
private Collection<E> delegate;
@Override
pub...
Converting 'ArrayList to 'String[]' in Java
...tring> list = new ArrayList<String>();
//add some stuff
list.add("android");
list.add("apple");
String[] stringArray = list.toArray(new String[0]);
The toArray() method without passing any argument returns Object[]. So you have to pass an array as an argument, which will be filled with th...