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What is the difference between JSON and Object Literal Notation?
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console.log('Object Literal : ', objLiteral ); // Object {foo: 42}foo: 42__proto__: Object
// This is a JSON String, like what you'd get back from an AJAX request.
var jsonString = '{"foo": 452}';
console.log('JOSN String : ', jsonString ); // {"foo": 452}
// This is how you deserialize that JSO...
MongoDB Aggregation: How to get total records count?
...te(array(
array('$match' => $document),
array('$group' => array('_id' => '$book_id', 'date' => array('$max' => '$book_viewed'), 'views' => array('$sum' => 1))),
array('$sort' => $sort),
// get total, AND preserve the results
array('$group' => array('_id' => nu...
hidden symbol ... is referenced by DSO 剖析 - C/C++ - 清泛网 - 专注C/C++及内核技术
...因是符号(函数)未导出导致的，添加导出申明即可解决：__attribute__ ((visibility("default")) DSO 是动态共享对象，Linux报“hidden symbol ... is referenced by DSO”错误的原因是符号(函数)未导出导致的，添加导出申明即可解决：
__attribute__ (...
C++简练易用的线程池(threadpool)及上下文隔离的无锁线程池(isolated_threa...
...易用的线程池(threadpool)及上下文隔离的无锁线程池(isolated_threadpool)完整实现本文主要介绍两种C++线程池模型完整代码，经过实战考验的，效率已极致优化的代码，可直接用于实际项目开发。1、C++简练易用的线程池(threadpool)
完整...
sys.argv[1] meaning in script
... prints the number of arguments, using the len function on the list.
from __future__ import print_function
import sys
print(sys.argv, len(sys.argv))
The script requires Python 2.6 or later. If you call this script print_args.py, you can invoke it with different arguments to see what happens.
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Can I get Memcached running on a Windows (x64) 64bit environment?
...x
http://allegiance.chi-town.com/Download.aspx?dl=Releases/MemCacheDManager_1_0_3_0.msi&rurl=MemCacheDManager.aspx
To unpack the msi:
msiexec /a Releases_MemCacheDManager_1_0_3_0.msi /qb TARGETDIR=c:\memcached
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Python 2.7 getting user input and manipulating as string without quotations
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Use raw_input() instead of input():
testVar = raw_input("Ask user for something.")
input() actually evaluates the input as Python code. I suggest to never use it. raw_input() returns the verbatim string entered by the user.
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Sorting Python list based on the length of the string
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def lensort(list_1):
list_2=[];list_3=[]
for i in list_1:
list_2.append([i,len(i)])
list_2.sort(key = lambda x : x[1])
for i in list_2:
list_3.append(i[0])
return list_3
This works for me!
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Execute code when Django starts ONCE only?
...d executed once.
urls.py
from django.confs.urls.defaults import *
from my_app import one_time_startup
urlpatterns = ...
one_time_startup()
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Rename a dictionary key
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For a regular dict, you can use:
mydict[new_key] = mydict.pop(old_key)
For an OrderedDict, I think you must build an entirely new one using a comprehension.
>>> OrderedDict(zip('123', 'abc'))
OrderedDict([('1', 'a'), ('2', 'b'), ('3', 'c')])
>>>...