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How do I get a value of a using jQuery?
...mment under his name you will notice that he did not write an attribute at all, it was <div 'item1'>, I guessed wrong apparently.
– Francisco Aquino
Dec 17 '09 at 12:19
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Rails: select unique values from a column
I already have a working solution, but I would really like to know why this doesn't work:
12 Answers
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Windows batch: sleep [duplicate]
...an into a funny issue using this method when I needed a script to automatically release the computer's IP address, wait a few minutes while I reconfigured a switch port, and then renew the IP address. During the intervening moments that the switch port was down, the network connection was lost and ...
jQuery Scroll to bottom of page/iframe
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There's actually no need to get the element's height: stackoverflow.com/a/44578849/1450294
– Michael Scheper
Jun 16 '17 at 0:10
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Visual Studio: How to show Overloads in IntelliSense?
...itten, the only way I know of to view the overloads for a method is to actually edit the method by deleting the Parenthesis () and reopening them.
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Appending to an object
...Query $.extend(obj1, obj2) would merge 2 objects for you, but you should really be using an array.
var alertsObj = {
1: {app:'helloworld','message'},
2: {app:'helloagain',message:'another message'}
};
var alertArr = [
{app:'helloworld','message'},
{app:'helloagain',message:'another...
Contains case insensitive
...= -1) {
The same can also be achieved using a Regular Expression (especially useful when you want to test against dynamic patterns):
if (!/Ral/i.test(referrer)) {
// ^i = Ignore case flag for RegExp
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How do I concatenate strings in Swift?
... + ""
str = "\(variable)"
str = str + "\(variable)"
I think I named them all.
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Flatten list of lists [duplicate]
...p evaluates MUCH faster than the unraveled loop and eliminates the append calls!
If you have multiple items in a sublist the list comp will even flatten that. ie
>>> list_of_lists = [[180.0, 1, 2, 3], [173.8], [164.2], [156.5], [147.2], [138.2]]
>>> flattened = [val for sublist...
Check if character is number?
...I think it's very fun to come up with ways to solve this. Below are some.
(All functions below assume argument is a single character. Change to n[0] to enforce it)
Method 1:
function isCharDigit(n){
return !!n.trim() && n > -1;
}
Method 2:
function isCharDigit(n){
return !!n.trim...