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What is the difference between `new Object()` and object literal notation?
...this.p);};
Both ways allow creation of instances of Obj like this:
var foo = new Obj( "hello" );
However, with the literal way, you carry a copy of the sayHello method within each instance of your objects. Whereas, with the prototype way, the method is defined in the object prototype and shar...
Why is the order in dictionaries and sets arbitrary?
...re listed in the order they currently reside in the table.
Take the keys 'foo' and 'bar', for example, and lets assume the table size is 8 slots. In Python 2.7, hash('foo') is -4177197833195190597, hash('bar') is 327024216814240868. Modulo 8, that means these two keys are slotted in slots 3 and 4 t...
A python class that acts like dict
...ode__(self):
return unicode(repr(self.__dict__))
o = Mapping()
o.foo = "bar"
o['lumberjack'] = 'foo'
o.update({'a': 'b'}, c=44)
print 'lumberjack' in o
print o
In [187]: run mapping.py
True
{'a': 'b', 'lumberjack': 'foo', 'foo': 'bar', 'c': 44}
...
Why does Pycharm's inspector complain about “d = {}”?
...o initialize dictionaries with single operation
d = {
'a': 12,
'b': 'foo',
'c': 'bar'
}
instead of many lines like
d = dict()
d['a'] = 12
d['b'] = ....
in the end I ended up with this:
d = dict()
d.update({
'a': 12,
'b': 'foo',
'c': 'bar'
})
Pycharm is not complaining on this
...
Package objects
...when you use the API defined by the package. Here is an example:
// file: foo/bar/package.scala
package foo
package object bar {
// package wide constants:
def BarVersionString = "1.0"
// or type aliases
type StringMap[+T] = Map[String,T]
// can be used to emulate a package wide impo...
Checking for NULL pointer in C/C++ [closed]
...
if (foo) is clear enough. Use it.
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How to print to stderr in Python?
...; print("Test")
Test
>>> eprint("Test")
Test
>>> eprint("foo", "bar", "baz", sep="---")
foo---bar---baz
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How do the PHP equality (== double equals) and identity (=== triple equals) comparison operators dif
..." is a string
1 == "1": true // "1" gets casted to an integer, which is 1
"foo" === "foo": true // both operands are strings and have the same value
Warning: two instances of the same class with equivalent members do NOT match the === operator. Example:
$a = new stdClass();
$a->foo = "bar";
$b ...
Passing parameters to a Bash function
... you need to call your function after it is declared.
#!/usr/bin/env sh
foo 1 # this will fail because foo has not been declared yet.
foo() {
echo "Parameter #1 is $1"
}
foo 2 # this will work.
Output:
./myScript.sh: line 2: foo: command not found
Parameter #1 is 2
Reference: Advanced...
MVC Razor view nested foreach's model
...='SomeProperty'>.
For a more complicated example, like model=>model.Foo.Bar.Baz.FooBar, it might generate <input name="Foo.Bar.Baz.FooBar" value="[whatever FooBar is]" />
Make sense? It is not just the work that the Func<> does, but how it does its work is important here.
(Note ...