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The easiest way to transform collection to array?
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Where x is the collection:
Foo[] foos = x.toArray(new Foo[x.size()]);
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How to find index of all occurrences of element in array?
...the index of all the instances of an element, say, "Nano", in a JavaScript array.
15 Answers
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Conversion of System.Array to List
...therwise. Hence I would like to know if it it possible to convert System.Array to List
10 Answers
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How to check if an element is in an array
In Swift, how can I check if an element exists in an array? Xcode does not have any suggestions for contain , include , or has , and a quick search through the book turned up nothing. Any idea how to check for this? I know that there is a method find that returns the index number, but is there ...
Numpy argsort - what is it doing?
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According to the documentation
Returns the indices that would sort an array.
2 is the index of 0.0.
3 is the index of 0.1.
1 is the index of 1.41.
0 is the index of 1.48.
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Array to Hash Ruby
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@tester, the * is called the splat operator. It takes an array and converts it a literal list of items. So *[1,2,3,4] => 1, 2, 3, 4. In this example, the above is equivalent to doing Hash["item 1", "item 2", "item 3", "item 4"]. And Hash has a [] method that accepts a list of ar...
Concatenating two one-dimensional NumPy arrays
I have two simple one-dimensional arrays in NumPy . I should be able to concatenate them using numpy.concatenate . But I get this error for the code below:
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Converting a JS object to an array using jQuery
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var myObj = {
1: [1, 2, 3],
2: [4, 5, 6]
};
var array = $.map(myObj, function(value, index) {
return [value];
});
console.log(array);
Output:
[[1, 2, 3], [4, 5, 6]]
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How to remove element from array in forEach loop?
I am trying to remove an element in an array in a forEach loop, but am having trouble with the standard solutions I've seen.
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do N times (declarative syntax)
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This answer is based on Array.forEach, without any library, just native vanilla.
To basically call something() 3 times, use:
[1,2,3].forEach(function(i) {
something();
});
considering the following function:
function something(){ console.log(...