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科大讯飞徐景明：从语音交互到人工智能 - 资讯 - 清泛网 - 专注C/C++及内核技术
...播电台的小姑娘说自己不像跟一群科学家在工作，反而像和民工一起……
现在看来，一切都值得。如今，刘庆峰和师兄弟们创立的科大讯飞，已经成为亚太地区最大的智能语音上市公司，在语音合成、语音识别、口语评测、自...
JSON parsing using Gson for Java
I would like to parse data from JSON which is of type String .
I am using Google Gson .
11 Answers
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Which $_SERVER variables are safe?
...ues are guaranteed to be the valid address of the client, as verified by a TCP/IP handshake. This is the address where any response will be sent to. REMOTE_HOST relies on reverse DNS lookups though and may hence be spoofed by DNS attacks against your server (in which case you have bigger problems an...
Why is JsonRequestBehavior needed?
Why is Json Request Behavior needed?
5 Answers
5
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Javascript: get package.json data in gulpfile.js
...gulp-specific question per-se, but how would one get info from the package.json file within the gulpfile.js; For instance, I want to get the homepage or the name and use it in a task.
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How to create index on JSON field in Postgres?
In PostgreSQL 9.3 Beta 2 (?), how do I create an index on a JSON field? I tried it using the -> operator used for hstore but got the following error:
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In Node.js, how do I turn a string to a json? [duplicate]
For example, a HTTP REST API just returned me a JSON, but of course it's a string right now. How can I turn it into a JSON?
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How to copy JavaScript object to new variable NOT by reference? [duplicate]
I wrote a quick jsfiddle here , where I pass a small JSON object to a new variable and modify the data from the original variable (not the new variable), but the new variable's data gets updated as well. This must mean that the JSON object was passed by reference, right?
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Ajax success event not working
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The result is probably not in JSON format, so when jQuery tries to parse it as such, it fails. You can catch the error with error: callback function.
You don't seem to need JSON in that function anyways, so you can also take out the dataType: 'json' row....
Ignore fields from Java object dynamically while sending as JSON from Spring MVC
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Add the @JsonIgnoreProperties("fieldname") annotation to your POJO.
Or you can use @JsonIgnore before the name of the field you want to ignore while deserializing JSON. Example:
@JsonIgnore
@JsonProperty(value = "user_password")
pu...