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计时器后台计时问题探究 - App Inventor 2 中文网 - 清泛IT社区，为创新赋能！
上午好，我用您提供的离线平台重新设计了一下程序，
用2种方法计算时间差，
1.开始时间与结束时间的时间差（秒），
2.计时器（时间间隔为1000）从开始时间开始，每运行1次就增加1秒，到结束时间得到的秒数累加。
从早...
用户反馈ble广播数据收不到 - 用户反馈 - 清泛IT社区，为创新赋能！
...联网:
你看看能搞定这一块吗？要是可以的话我就先买个离线版的，在线的太慢了
清泛:
ble 广播用法不常见，也不太安全，目前就之前一个用户反馈要这个功能，应该是成功过的。这块我还没有实地测试，后续我会用硬件测...
MQTT支持获取设备端的在线状态吗？ - 创客硬件开发 - 清泛IT社区，为创新赋能！
mqtt拓展支持获取设备端的在线状态吗？这里仅仅提供一个思路：
设备状态是设备的一项数据，这个也需要设备上报其状态数据给app端，类似网络的心跳包，定时上报状态数据，一定时间没取到数据就认为设备离线。
Do copyright dates need to be updated? [closed]
...rotection. See § 408. Although registration of a work with the Copyright Office is not a precondition for protection, an action for copyright infringement may not be commenced until the copyright has been formally registered with the Copyright Office. See § 411.
Deposit of copies with the Copyri...
/data/user/0/xxxx/files（内部存储）和 /storage/emulated/0/Android/data...
...：
当需要存储以下内容时：
大型文件（如视频缓存、离线地图）。允许用户通过文件管理器查看（但不可修改）的文件。需要跨应用共享但不想使用 MediaStore 的文件（通过 FileProvider 共享）。
6. 代码示例(1) 写入内部存储
// ...
Freezing Row 1 and Column A at the same time
...Reference Guide (More Complicated, but resourceful none the less) - http://office.microsoft.com/en-us/excel-help/freeze-or-lock-rows-and-columns-HP010342542.aspx
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Remove all breakpoints in IntelliJ IDEA
... answered Aug 6 '16 at 9:05
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Generating random integer from a range
...s code that generates a million random ints uniformly distributed in [-57, 365]. I've used the new std <chrono> facilities to time it as you mentioned performance is a major concern for you.
#include <iostream>
#include <random>
#include <chrono>
int main()
{
typedef s...
Safely limiting Ansible playbooks to a single machine?
...k with a group of hosts:
$ ansible-playbook user.yml --extra-vars "target=office" --list-hosts
playbook: user.yml
play #1 (office): host count=3
imac-1.local
imac-2.local
imac-3.local
Forgetting to define hosts is safe!
$ ansible-playbook user.yml --list-hosts
playbook: user.yml...
Are there any O(1/n) algorithms?
...nswer:
Do any two people in a set have the same birthday? When n exceeds 365, return true. Although for less than 365, this is O(n ln n). Perhaps not a great answer since the problem doesn't slowly get easier but just becomes O(1) for n > 365.
...