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Insert new item in array on any position in PHP
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Also in PHP manual, example #1: php.net/manual/en/function.array-splice.php
– marcovtwout
Dec 3 '12 at 13:16
3
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PHP: Count a stdClass object
...od works, I would not use it for implementation because future versions of PHP could cause this code to break, I much prefer Alan Strom's answer.
– ars265
Jul 14 '13 at 12:32
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Import a file from a subdirectory?
...nguage shouldn't impose its way of loading files across the filesystem. In PHP we solved the problem by letting the userland code register multiple autoloading functions that are called when a namespace/class is missing. Then the community has produced the PSR-4 standard and Composer implements it, ...
How do I install a custom font on an HTML site
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Yes, you can use the CSS feature named @font-face.
It has only been officially approved in CSS3, but been proposed and implemented in CSS2 and has been supported in IE for quite a long time.
You declare it in the CSS like this:
@font-face { font-family: Delicious; src: url('Delicious-Roman.otf')...
how do i remove a comma off the end of a string?
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Thank you, I was doing this with substr, strlen,... all my life
– Farhad
Apr 15 '15 at 17:59
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Keep file in a Git repo, but don't track changes
...ut git status keep telling the file is modified
– rraallvv
Dec 21 '13 at 20:43
7
Yeah, this shoul...
Determine the line of code that causes a segmentation fault?
...e tutorial to get you started with GDB.
Where the segfault occurs is generally only a clue as to where "the mistake which causes" it is in the code. The given location is not necessarily where the problem resides.
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StatusbarTools 扩展 - 状态栏自定义工具 · App Inventor 2 中文网
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StatusbarTools 扩展
StatusbarTools扩展为App Inventor开发者提供了强大的状态栏自...
How to create an array from a CSV file using PHP and the fgetcsv function
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FYI: str_getcsv() is only available from PHP 5.3.0 on. The project I am working on missed it by 1 version DOH! (we are using 5.2.9 atm).
– Jim Ford
Sep 16 '09 at 19:15
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How do you create optional arguments in php?
...ument must be a constant expression. It can't be a variable or a function call.
If you need this functionality however:
function foo($foo, $bar = false)
{
if(!$bar)
{
$bar = $foo;
}
}
Assuming $bar isn't expected to be a boolean of course.
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