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0.1 float is greater than 0.1 double. I expected it to be false [duplicate]

...loat. float has 24 binary bits of precision, and double has 53. In binary, 0.1 is: 0.1₁₀ = 0.0001100110011001100110011001100110011001100110011…₂ ^ ^ ^ ^ 1 10 20 24 So if we round up at the 24th digit, we'll get 0.1₁₀ ~ 0.00011...
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How to check if all elements of a list matches a condition?

I have a list consisting of like 20000 lists. I use each list's 3rd element as a flag. I want to do some operations on this list as long as at least one element's flag is 0, it's like: ...
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What's the simplest way to test whether a number is a power of 2 in C++?

... 190 (n & (n - 1)) == 0 is best. However, note that it will incorrectly return true for n=0, so i...
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Current time formatting with Javascript

...ar() - Returns the 4-digit year getMonth() - Returns a zero-based integer (0-11) representing the month of the year. getDate() - Returns the day of the month (1-31). getDay() - Returns the day of the week (0-6). 0 is Sunday, 6 is Saturday. getHours() - Returns the hour of the day (0-23). getMinutes...
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Check substring exists in a string in C

... 280 if(strstr(sent, word) != NULL) { /* ... */ } Note that strstr returns a pointer to the sta...
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Specifying rails version to use when creating a new application

I have two versions of rails (2.1.0 and 2.2.2) installed in my computer. 7 Answers 7 ...
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Memoization in Haskell?

...efficiently the following function in Haskell, for large numbers (n > 108) 8 Answers ...
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Android Left to Right slide animation

...ndroid:shareInterpolator="false"> <translate android:fromXDelta="-100%" android:toXDelta="0%" android:fromYDelta="0%" android:toYDelta="0%" android:duration="700"/> </set> This is for right to left animation: <set xmlns:android="http://schemas.android...
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Gray out image with CSS?

...age" src="something.jpg" /> </div> css: #myImage { opacity: 0.4; filter: alpha(opacity=40); /* msie */ } /* or */ #wrapper { opacity: 0.4; filter: alpha(opacity=40); /* msie */ background-color: #000; } ...
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Compare double to zero using epsilon

...there is a 52-bit mantissa and 11-bit exponent. Let's break it to bits: 1.0000 00000000 00000000 00000000 00000000 00000000 00000000 × 2^0 = 1 The smallest representable number greater than 1: 1.0000 00000000 00000000 00000000 00000000 00000000 00000001 × 2^0 = 1 + 2^-52 Therefore: epsilon ...