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How do you get a query string on Flask?
Not obvious from the flask documention on how to get the query string. I am new, looked at the docs, could not find!
9 A...
How to compare type of an object in Python?
Basically I want to do this:
14 Answers
14
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What does the Reflect object do in JavaScript?
...nd anything on Google. Today I found this http://people.mozilla.org/~jorendorff/es6-draft.html#sec-reflect-object and it sounds similar to the Proxy object apart from the realm and loader functionality.
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Declaring variables inside loops, good practice or bad practice?
...me name somewhere later in your code (can also be mitigated using the -Wshadow warning instruction on GCC)
The compiler knows that the variable scope is limited to inside the loop, and therefore will issue a proper error message if the variable is by mistake referenced elsewhere.
Last but not least,...
Does Git publicly expose my e-mail address?
... should go into the config and specify my name and my e-mail address. They don't elaborate; they just say to do it.
8 Answe...
How do I include a file over 2 directories back?
How do you include a file that is more than 2 directories back. I know you can use ../index.php to include a file that is 2 directories back, but how do you do it for 3 directories back?
Does this make sense?
I tried .../index.php but it isn't working.
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JavaScript, Node.js: is Array.forEach asynchronous?
...uestion regarding the native Array.forEach implementation of JavaScript: Does it behave asynchronously?
For example, if I call:
...
Creating multiline strings in JavaScript
...use transpilers to be more compatible.
Original ES5 answer:
Javascript doesn't have a here-document syntax. You can escape the literal newline, however, which comes close:
"foo \
bar"
share
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Remove blue border from css custom-styled button in Chrome
...utline: none } or button:focus { outline:none } would work, but neither do. Any ideas?
22 Answers
...
How do I compare two hashes?
...sh3.to_a
=> [["c", 3]]
Hash[*difference.flatten]
=> {"c"=>3}
Doing it all in one operation and getting rid of the difference variable:
Hash[*(
(hash3.size > hash1.size) \
? hash3.to_a - hash1.to_a \
: hash1.to_a - hash3.to_a
).flatten]
=> {"c"=>3}
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