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How do you check whether a number is divisible by another number (Python)?
I need to test whether each number from 1 to 1000 is a multiple of 3 or a multiple of 5. The way I thought I'd do this would be to divide the number by 3, and if the result is an integer then it would be a multiple of 3. Same with 5.
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How do you plot bar charts in gnuplot?
...ar graph:
set boxwidth 0.5
set style fill solid
plot "data.dat" using 1:3:xtic(2) with boxes
data.dat:
0 label 100
1 label2 450
2 "bar label" 75
If you want to style your bars differently, you can do something like:
set style line 1 lc rgb "red"
set style line 2 lc rgb "blue"
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Most efficient way of making an if-elif-elif-else statement when the else is done the most?
...:
the_thing = 2
elif something == 'there':
the_thing = 3
else:
the_thing = 4
2.py
something = 'something'
options = {'this': 1, 'that': 2, 'there': 3}
for i in xrange(1000000):
the_thing = options.get(something, 4)
3.py
something = 'something'
options = {'t...
What are the aspect ratios for all Android phone and tablet devices?
...═════════════════╣
║ 5 x 3 ║ 0.6 ║ 1.667... ║
╠══════════════════════════╬════════════════════════...
How to print third column to last column?
... DbgView log file. I can't seem to find an example that prints from column 3 onwards until the end of the line. Note that each line has variable number of columns.
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How does virtual inheritance solve the “diamond” (multiple inheritance) ambiguity?
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edited Apr 23 '18 at 5:23
StoryTeller - Unslander Monica
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App Inventor 2 数学积木完全指南：从加减乘除到位运算，一篇搞定所有计算...
...现三个甚至更多数字同时运算：
加法： 1 + 2 + 3 + 4 = 10 （一个积木搞定，不用嵌套）
乘法： 2 x 3 x 4 = 24 （同理，一个积木搞定）
幂运算积木 ^ 也非常实用：2 ^ 3 = 8，...
Double vs. BigDecimal?
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463
A BigDecimal is an exact way of representing numbers. A Double has a certain precision. Working ...
How to use string.replace() in python 3.x
The string.replace() is deprecated on python 3.x. What is the new way of doing this?
8 Answers
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Access lapply index names inside FUN
...uments to the function, so the following works:
x <- list(a=11,b=12,c=13) # Changed to list to address concerns in commments
lapply(seq_along(x), function(y, n, i) { paste(n[[i]], y[[i]]) }, y=x, n=names(x))
Here I use lapply over the indices of x, but also pass in x and the names of x. As you...