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Cannot pass null argument when using type hinting
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PHP 7.1 or newer (released 2nd December 2016)
You can explicitly declare a variable to be null with this syntax
function foo(?Type $t) {
}
this will result in
$this->foo(new Type()); // ok
$this->foo(null); // ok
$this->foo(); // error
So, if you want...
How to dismiss ViewController in Swift?
... NoozZoon Nooz
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6
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How do I convert from stringstream to string in C++?
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answered Mar 19 '09 at 16:38
Tyler McHenryTyler McHenry
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How to get a JavaScript object's class?
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edited Sep 16 '16 at 16:00
James L.
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How do I return rows with a specific value first?
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edited Aug 9 '16 at 21:25
answered Aug 9 '09 at 1:57
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Dynamically Changing log4j log level
...etLevel(Level.FATAL);
– CelinHC
Oct 16 '11 at 18:38
8
Note that the log4j 2 API does not provide ...
Adding minutes to date time in PHP
... What does 'PT' represent?
– NicholasJohn16
Jul 18 '16 at 21:43
1
@bozdoz It's not a ...
Getting number of elements in an iterator in Python
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16 Answers
16
Active
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Restart/undo conflict resolution in a single file
... (in conflict state)
– Gaui
Apr 25 '16 at 20:18
1
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What to do with commit made in a detached head
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answered Aug 19 '11 at 16:19
Ryan StewartRyan Stewart
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