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Force drop mysql bypassing foreign key constraint

... answered Feb 19 '10 at 23:53 Otávio DécioOtávio Décio 68.9k1414 gold badges152152 silver badges219219 bronze badges ...
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C#: Looping through lines of multiline string

... answered Sep 30 '09 at 19:41 Jon SkeetJon Skeet 1211k772772 gold badges85588558 silver badges88218821 bronze badges ...
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Why should I use tags vs. release/beta branches for versioning?

...ow is why use tagging at all if I can just create a new branch called 1.1.0 and not have to cloud my mind with a whole new set of git commands? ...
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Query for array elements inside JSON type

... | edited Jun 20 at 9:12 Community♦ 111 silver badge answered Mar 29 '14 at 22:25 ...
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How to wait in bash for several subprocesses to finish and return exit code !=0 when any subprocess

...ral subprocesses spawned from that script to finish and return exit code !=0 when any of the subprocesses ends with code !=0 ? ...
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Logical XOR operator in C++?

... answered Oct 20 '09 at 19:03 Greg HewgillGreg Hewgill 783k167167 gold badges10841084 silver badges12221222 bronze badges ...
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Populate data table from data reader

I'm doing a basic thing in C# (MS VS2008) and have a question more about proper design than specific code. 5 Answers ...
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Do I need a Global.asax.cs file at all if I'm using an OWIN Startup.cs class and move all configurat

... dmatsondmatson 5,79111 gold badge2020 silver badges2121 bronze badges 19 ...
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How to scale SVG image to fill browser window?

... How about: html, body { margin:0; padding:0; overflow:hidden } svg { position:fixed; top:0; bottom:0; left:0; right:0 } Or: html, body { margin:0; padding:0; overflow:hidden } svg { position:fixed; top:0; left:0; height:100%; width:100% } I have an ex...
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Finding three elements in an array whose sum is closest to a given number

... >= j) { // We got a match! All done. if (A[i] + A[j] + A[k] == 0) return (A[i], A[j], A[k]) // We didn't match. Let's try to get a little closer: // If the sum was too big, decrement k. // If the sum was too small, increment j. (A[i] + A[j] + A[k] > 0) ? k-- : j++...